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Celestial orbit whose trajectory is a conic section in the orbital plane
πŸ‘ Image
An elliptic Kepler orbit with an eccentricity of 0.7, a parabolic Kepler orbit and a hyperbolic Kepler orbit with an eccentricity of 1.3. The distance to the focal point is a function of the polar angle relative to the horizontal line as given by the equation (13)

In celestial mechanics, a Kepler orbit (or Keplerian orbit, named after the German astronomer Johannes Kepler) is the motion of one body relative to another, as an ellipse, parabola, or hyperbola, which forms a two-dimensional orbital plane in three-dimensional space. A Kepler orbit can also tend towards a straight line. It considers only the point-like gravitational attraction of two bodies, neglecting perturbations due to gravitational interactions with other objects, atmospheric drag, solar radiation pressure, a non-spherical central body, and so on. It is thus said to be a solution of a special case of the two-body problem, known as the Kepler problem. As a theory in classical mechanics, it also does not take into account the effects of general relativity. Keplerian orbits can be parametrized into six orbital elements in various ways.

In most applications, there is a large central body, the center of mass of which is assumed to be the center of mass of the entire system. By decomposition, the orbits of two objects of similar mass can be described as Kepler orbits around their common center of mass, their barycenter.

Introduction

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From ancient times until the 16th and 17th centuries, the motions of the planets were believed to follow perfectly circular geocentric paths as taught by the ancient Greek philosophers Aristotle and Ptolemy. Variations in the motions of the planets were explained by smaller circular paths overlaid on the larger path (see epicycle). As measurements of the planets became increasingly accurate, revisions to the theory were proposed. In 1543, Nicolaus Copernicus published a heliocentric model of the Solar System, although he still believed that the planets traveled in perfectly circular paths centered on the Sun.[1]

Development of the laws

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In 1601, Johannes Kepler acquired the extensive, meticulous observations of the planets made by Tycho Brahe. Kepler would spend the next five years trying to fit the observations of the planet Mars to various curves. In 1609, Kepler published the first two of his three laws of planetary motion. The first law states:

The orbit of every planet is an ellipse with the sun at a focus.

More generally, the path of an object undergoing Keplerian motion may also follow a parabola or a hyperbola, which, along with ellipses, belong to a group of curves known as conic sections. Mathematically, the distance between a central body and an orbiting body can be expressed as:

πŸ‘ {\displaystyle r(\theta )={\frac {a(1-e^{2})}{1+e\cos(\theta )}}}

where:

Alternately, the equation can be expressed as:

πŸ‘ {\displaystyle r(\theta )={\frac {p}{1+e\cos(\theta )}}}

Where πŸ‘ {\displaystyle p}
is called the semi-latus rectum of the curve. This form of the equation is particularly useful when dealing with parabolic trajectories, for which the semi-major axis is infinite.

Despite developing these laws from observations, Kepler was never able to develop a theory to explain these motions.[2] Isaac Newton produced the first such theory based around the concept of gravity. Albert Einstein's general relativity is the current description of gravitation in modern physics. The two-body problem in general relativity has no closed-form solutions.

Isaac Newton

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Between 1665 and 1666, Isaac Newton developed several concepts related to motion, gravitation and differential calculus. However, these concepts were not published until 1687 in the Principia, in which he outlined his laws of motion and his law of universal gravitation. His second of his three laws of motion states:

The acceleration of a body is parallel and directly proportional to the net force acting on the body, is in the direction of the net force, and is inversely proportional to the mass of the body:

πŸ‘ {\displaystyle \mathbf {F} =m\mathbf {a} =m{\frac {d^{2}\mathbf {r} }{dt^{2}}}}

Where:

Strictly speaking, this form of the equation only applies to an object of constant mass, which holds true based on the simplifying assumptions made below.

πŸ‘ Image
The mechanisms of Newton's law of universal gravitation; a point mass m1 attracts another point mass m2 by a force F2 which is proportional to the product of the two masses and inversely proportional to the square of the distance (r) between them. Regardless of masses or distance, the magnitudes of |F1| and |F2| will always be equal. G is the gravitational constant.

Newton's law of gravitation states:

Every point mass attracts every other point mass by a force pointing along the line intersecting both points. The force is proportional to the product of the two masses and inversely proportional to the square of the distance between the point masses:

πŸ‘ {\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}}

where:

From the laws of motion and the law of universal gravitation, Newton was able to derive Kepler's laws, which are specific to orbital motion in astronomy. Since Kepler's laws were well-supported by observation data, this consistency provided strong support of the validity of Newton's generalized theory, and unified celestial and ordinary mechanics. These laws of motion formed the basis of modern celestial mechanics until Albert Einstein introduced the concepts of special and general relativity in the early 20th century. For most applications, Keplerian motion approximates the motions of planets and satellites to relatively high degrees of accuracy and is used extensively in astronomy and astrodynamics.

Simplified two body problem

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To solve for the motion of an object in a two body system, two simplifying assumptions can be made:

  1. The bodies are spherically symmetric and can be treated as point masses.
  2. There are no external or internal forces acting upon the bodies other than their mutual gravitation.

The shapes of large celestial bodies are close to spheres. By symmetry, the net gravitational force attracting a mass point towards a homogeneous sphere must be directed towards its centre. The shell theorem (also proven by Isaac Newton) states that the magnitude of this force is the same as if all mass was concentrated in the middle of the sphere, even if the density of the sphere varies with depth (as it does for most celestial bodies). From this immediately follows that the attraction between two homogeneous spheres is as if both had its mass concentrated to its center.

Smaller objects, like asteroids or spacecraft often have a shape strongly deviating from a sphere. But the gravitational forces produced by these irregularities are generally small compared to the gravity of the central body. The difference between an irregular shape and a perfect sphere also diminishes with distances, and most orbital distances are very large when compared with the diameter of a small orbiting body. Thus for some applications, shape irregularity can be neglected without significant impact on accuracy. This effect is quite noticeable for artificial Earth satellites, especially those in low orbits.

Planets rotate at varying rates and thus may take a slightly oblate shape because of the centrifugal force. With such an oblate shape, the gravitational attraction will deviate somewhat from that of a homogeneous sphere. At larger distances the effect of this oblateness becomes negligible. Planetary motions in the Solar System can be computed with sufficient precision if they are treated as point masses.

Two point mass objects with masses πŸ‘ {\displaystyle m_{1}}
and πŸ‘ {\displaystyle m_{2}}
and position vectors πŸ‘ {\displaystyle \mathbf {r} _{1}}
and πŸ‘ {\displaystyle \mathbf {r} _{2}}
relative to some inertial reference frame experience gravitational forces:

πŸ‘ {\displaystyle m_{1}{\ddot {\mathbf {r} }}_{1}={\frac {-Gm_{1}m_{2}}{r^{2}}}\mathbf {\hat {r}} }
πŸ‘ {\displaystyle m_{2}{\ddot {\mathbf {r} }}_{2}={\frac {Gm_{1}m_{2}}{r^{2}}}\mathbf {\hat {r}} }

where πŸ‘ {\displaystyle \mathbf {r} }
is the relative position vector of mass 1 with respect to mass 2, expressed as:

πŸ‘ {\displaystyle \mathbf {r} =\mathbf {r} _{1}-\mathbf {r} _{2}}

and πŸ‘ {\displaystyle \mathbf {\hat {r}} }
is the unit vector in that direction and πŸ‘ {\displaystyle r}
is the length of that vector.

Dividing by their respective masses and subtracting the second equation from the first yields the equation of motion for the acceleration of the first object with respect to the second:

πŸ‘ {\displaystyle {\ddot {\mathbf {r} }}=-{\frac {\alpha }{r^{2}}}\mathbf {\hat {r}} }
1

where πŸ‘ {\displaystyle \alpha }
is the gravitational parameter and is equal to

πŸ‘ {\displaystyle \alpha =G(m_{1}+m_{2})}

In many applications, a third simplifying assumption can be made:

  1. When compared to the central body, the mass of the orbiting body is insignificant. Mathematically, m1 >> m2, so Ξ± = G (m1 + m2) β‰ˆ Gm1. Such standard gravitational parameters, often denoted as πŸ‘ {\displaystyle \mu =G\,M}
    , are widely available for Sun, major planets and Moon, which have much larger masses πŸ‘ {\displaystyle M}
    than their orbiting satellites.

This assumption is not necessary to solve the simplified two body problem, but it simplifies calculations, particularly with Earth-orbiting satellites and planets orbiting the Sun. Even Jupiter's mass is less than the Sun's by a factor of 1047,[3] which would constitute an error of 0.096% in the value of Ξ±. Notable exceptions include the Earth-Moon system (mass ratio of 81.3), the Pluto-Charon system (mass ratio of 8.9) and binary star systems.

Under these assumptions the differential equation for the two body case can be completely solved mathematically and the resulting orbit which follows Kepler's laws of planetary motion is called a "Kepler orbit". The orbits of all planets are to high accuracy Kepler orbits around the Sun. The small deviations are due to the much weaker gravitational attractions between the planets, and in the case of Mercury, due to general relativity. The orbits of the artificial satellites around the Earth are, with a fair approximation, Kepler orbits with small perturbations due to the gravitational attraction of the Sun, the Moon and the oblateness of the Earth. In high accuracy applications for which the equation of motion must be integrated numerically with all gravitational and non-gravitational forces (such as solar radiation pressure and atmospheric drag) being taken into account, the Kepler orbit concepts are of paramount importance and heavily used.

Keplerian elements

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πŸ‘ Image
Keplerian orbital elements.

Any Keplerian trajectory can be defined by six parameters. The motion of an object moving in three-dimensional space is characterized by a position vector and a velocity vector. Each vector has three components, so the total number of values needed to define a trajectory through space is six. An orbit is generally defined by six elements (known as Keplerian elements) that can be computed from position and velocity, three of which have already been discussed. These elements are convenient in that of the six, five are unchanging for an unperturbed orbit (a stark contrast to two constantly changing vectors). The future location of an object within its orbit can be predicted and its new position and velocity can be easily obtained from the orbital elements.

Two define the size and shape of the trajectory:

Three define the orientation of the orbital plane:

And finally:

Because πŸ‘ {\displaystyle i}
, πŸ‘ {\displaystyle \Omega }
and πŸ‘ {\displaystyle \omega }
are simply angular measurements defining the orientation of the trajectory in the reference frame, they are not strictly necessary when discussing the motion of the object within the orbital plane. They have been mentioned here for completeness, but are not required for the proofs below.

Mathematical solution of the differential equation (1) above

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For movement under any central force, i.e. a force parallel to r, the specific relative angular momentum πŸ‘ {\displaystyle \mathbf {H} =\mathbf {r} \times {\dot {\mathbf {r} }}}
stays constant: πŸ‘ {\displaystyle {\dot {\mathbf {H} }}={\frac {d}{dt}}\left(\mathbf {r} \times {\dot {\mathbf {r} }}\right)={\dot {\mathbf {r} }}\times {\dot {\mathbf {r} }}+\mathbf {r} \times {\ddot {\mathbf {r} }}=\mathbf {0} +\mathbf {0} =\mathbf {0} }

Since the cross product of the position vector and its velocity stays constant, they must lie in the same plane, orthogonal to πŸ‘ {\displaystyle \mathbf {H} }
. This implies the vector function is a plane curve.

Because the equation has symmetry around its origin, it is easier to solve in polar coordinates. However, it is important to note that equation (1) refers to linear acceleration πŸ‘ {\displaystyle \left({\ddot {\mathbf {r} }}\right),}
as opposed to angular πŸ‘ {\displaystyle \left({\ddot {\theta }}\right)}
or radial πŸ‘ {\displaystyle \left({\ddot {r}}\right)}
acceleration. Therefore, one must be cautious when transforming the equation. Introducing a cartesian coordinate system πŸ‘ {\displaystyle ({\hat {\mathbf {x} }},{\hat {\mathbf {y} }})}
and polar unit vectors πŸ‘ {\displaystyle ({\hat {\mathbf {r} }},{\hat {\mathbf {q} }})}
in the plane orthogonal to πŸ‘ {\displaystyle \mathbf {H} }
:

πŸ‘ {\displaystyle {\begin{aligned}{\hat {\mathbf {r} }}&=\cos {\theta }{\hat {\mathbf {x} }}+\sin {\theta }{\hat {\mathbf {y} }}\\{\hat {\mathbf {q} }}&=-\sin {\theta }{\hat {\mathbf {x} }}+\cos {\theta }{\hat {\mathbf {y} }}\end{aligned}}}

We can now rewrite the vector function πŸ‘ {\displaystyle \mathbf {r} }
and its derivatives as:

πŸ‘ {\displaystyle {\begin{aligned}\mathbf {r} &=r\left(\cos \theta {\hat {\mathbf {x} }}+\sin \theta {\hat {\mathbf {y} }}\right)=r{\hat {\mathbf {r} }}\\{\dot {\mathbf {r} }}&={\dot {r}}{\hat {\mathbf {r} }}+r{\dot {\theta }}{\hat {\mathbf {q} }}\\{\ddot {\mathbf {r} }}&=\left({\ddot {r}}-r{\dot {\theta }}^{2}\right){\hat {\mathbf {r} }}+\left(r{\ddot {\theta }}+2{\dot {r}}{\dot {\theta }}\right){\hat {\mathbf {q} }}\end{aligned}}}

(see "Vector calculus"). Substituting these into (1), we find: πŸ‘ {\displaystyle \left({\ddot {r}}-r{\dot {\theta }}^{2}\right){\hat {\mathbf {r} }}+\left(r{\ddot {\theta }}+2{\dot {r}}{\dot {\theta }}\right){\hat {\mathbf {q} }}=\left(-{\frac {\alpha }{r^{2}}}\right){\hat {\mathbf {r} }}+(0){\hat {\mathbf {q} }}}

This gives the ordinary differential equation in the two variables πŸ‘ {\displaystyle r}
and πŸ‘ {\displaystyle \theta }
:

πŸ‘ {\displaystyle {\ddot {r}}-r{\dot {\theta }}^{2}=-{\frac {\alpha }{r^{2}}}}
2

In order to solve this equation, all time derivatives must be eliminated. This brings: πŸ‘ {\displaystyle H=|\mathbf {r} \times {\dot {\mathbf {r} }}|=\left|{\begin{pmatrix}r\cos(\theta )\\r\sin(\theta )\\0\end{pmatrix}}\times {\begin{pmatrix}{\dot {r}}\cos(\theta )-r\sin(\theta ){\dot {\theta }}\\{\dot {r}}\sin(\theta )+r\cos(\theta ){\dot {\theta }}\\0\end{pmatrix}}\right|=\left|{\begin{pmatrix}0\\0\\r^{2}{\dot {\theta }}\end{pmatrix}}\right|=r^{2}{\dot {\theta }}}

πŸ‘ {\displaystyle {\dot {\theta }}={\frac {H}{r^{2}}}}
3

Taking the time derivative of (3) gets

πŸ‘ {\displaystyle {\ddot {\theta }}=-{\frac {2\cdot H\cdot {\dot {r}}}{r^{3}}}}
4

Equations (3) and (4) allow us to eliminate the time derivatives of πŸ‘ {\displaystyle \theta }
. In order to eliminate the time derivatives of πŸ‘ {\displaystyle r}
, the chain rule is used to find appropriate substitutions:

πŸ‘ {\displaystyle {\dot {r}}={\frac {dr}{d\theta }}\cdot {\dot {\theta }}}
5
πŸ‘ {\displaystyle {\ddot {r}}={\frac {d^{2}r}{d\theta ^{2}}}\cdot {\dot {\theta }}^{2}+{\frac {dr}{d\theta }}\cdot {\ddot {\theta }}}
6

Using these four substitutions, all time derivatives in (2) can be eliminated, yielding an ordinary differential equation for πŸ‘ {\displaystyle r}
as function of πŸ‘ {\displaystyle \theta .}
πŸ‘ {\displaystyle {\ddot {r}}-r{\dot {\theta }}^{2}=-{\frac {\alpha }{r^{2}}}}
πŸ‘ {\displaystyle {\frac {d^{2}r}{d\theta ^{2}}}\cdot {\dot {\theta }}^{2}+{\frac {dr}{d\theta }}\cdot {\ddot {\theta }}-r{\dot {\theta }}^{2}=-{\frac {\alpha }{r^{2}}}}
πŸ‘ {\displaystyle {\frac {d^{2}r}{d\theta ^{2}}}\cdot \left({\frac {H}{r^{2}}}\right)^{2}+{\frac {dr}{d\theta }}\cdot \left(-{\frac {2\cdot H\cdot {\dot {r}}}{r^{3}}}\right)-r\left({\frac {H}{r^{2}}}\right)^{2}=-{\frac {\alpha }{r^{2}}}}

πŸ‘ {\displaystyle {\frac {H^{2}}{r^{4}}}\cdot \left({\frac {d^{2}r}{d\theta ^{2}}}-2\cdot {\frac {\left({\frac {dr}{d\theta }}\right)^{2}}{r}}-r\right)=-{\frac {\alpha }{r^{2}}}}
7

The differential equation (7) can be solved analytically by the variable substitution

πŸ‘ {\displaystyle r={\frac {1}{s}}}
8

Using the chain rule for differentiation gets:

πŸ‘ {\displaystyle {\frac {dr}{d\theta }}=-{\frac {1}{s^{2}}}\cdot {\frac {ds}{d\theta }}}
9
πŸ‘ {\displaystyle {\frac {d^{2}r}{d\theta ^{2}}}={\frac {2}{s^{3}}}\cdot \left({\frac {ds}{d\theta }}\right)^{2}-{\frac {1}{s^{2}}}\cdot {\frac {d^{2}s}{d\theta ^{2}}}}
10

Using the expressions (10) and (9) for πŸ‘ {\displaystyle {\frac {d^{2}r}{d\theta ^{2}}}}
and πŸ‘ {\displaystyle {\frac {dr}{d\theta }}}
gets

πŸ‘ {\displaystyle H^{2}\cdot \left({\frac {d^{2}s}{d\theta ^{2}}}+s\right)=\alpha }
11

with the general solution

πŸ‘ {\displaystyle s={\frac {\alpha }{H^{2}}}\cdot \left(1+e\cdot \cos(\theta -\theta _{0})\right)}
12

where e and πŸ‘ {\displaystyle \theta _{0}}
are constants of integration depending on the initial values for s and πŸ‘ {\displaystyle {\tfrac {ds}{d\theta }}.}

Instead of using the constant of integration πŸ‘ {\displaystyle \theta _{0}}
explicitly one introduces the convention that the unit vectors πŸ‘ {\displaystyle {\hat {x}},{\hat {y}}}
defining the coordinate system in the orbital plane are selected such that πŸ‘ {\displaystyle \theta _{0}}
takes the value zero and e is positive. This then means that πŸ‘ {\displaystyle \theta }
is zero at the point where πŸ‘ {\displaystyle s}
is maximal and therefore πŸ‘ {\displaystyle r={\tfrac {1}{s}}}
is minimal. Defining the parameter p as πŸ‘ {\displaystyle {\tfrac {H^{2}}{\alpha }}}
one has that

πŸ‘ {\displaystyle r={\frac {1}{s}}={\frac {p}{1+e\cdot \cos \theta }}}

Alternate derivation

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Another way to solve this equation without the use of polar differential equations is as follows:

Define a unit vector πŸ‘ {\displaystyle \mathbf {u} }
, πŸ‘ {\displaystyle \mathbf {u} ={\frac {\mathbf {r} }{r}}}
, such that πŸ‘ {\displaystyle \mathbf {r} =r\mathbf {u} }
and πŸ‘ {\displaystyle {\ddot {\mathbf {r} }}=-{\tfrac {\alpha }{r^{2}}}\mathbf {u} }
. It follows that πŸ‘ {\displaystyle \mathbf {H} =\mathbf {r} \times {\dot {\mathbf {r} }}=r\mathbf {u} \times {\frac {d}{dt}}(r\mathbf {u} )=r\mathbf {u} \times (r{\dot {\mathbf {u} }}+{\dot {r}}\mathbf {u} )=r^{2}(\mathbf {u} \times {\dot {\mathbf {u} }})+r{\dot {r}}(\mathbf {u} \times \mathbf {u} )=r^{2}\mathbf {u} \times {\dot {\mathbf {u} }}}

Now consider πŸ‘ {\displaystyle {\ddot {\mathbf {r} }}\times \mathbf {H} =-{\frac {\alpha }{r^{2}}}\mathbf {u} \times (r^{2}\mathbf {u} \times {\dot {\mathbf {u} }})=-\alpha \mathbf {u} \times (\mathbf {u} \times {\dot {\mathbf {u} }})=-\alpha [(\mathbf {u} \cdot {\dot {\mathbf {u} }})\mathbf {u} -(\mathbf {u} \cdot \mathbf {u} ){\dot {\mathbf {u} }}]}

(see Vector triple product). Notice that πŸ‘ {\displaystyle \mathbf {u} \cdot \mathbf {u} =|\mathbf {u} |^{2}=1}
πŸ‘ {\displaystyle \mathbf {u} \cdot {\dot {\mathbf {u} }}={\frac {1}{2}}(\mathbf {u} \cdot {\dot {\mathbf {u} }}+{\dot {\mathbf {u} }}\cdot \mathbf {u} )={\frac {1}{2}}{\frac {d}{dt}}(\mathbf {u} \cdot \mathbf {u} )=0}

Substituting these values into the previous equation gives: πŸ‘ {\displaystyle {\ddot {\mathbf {r} }}\times \mathbf {H} =\alpha {\dot {\mathbf {u} }}}

Integrating both sides: πŸ‘ {\displaystyle {\dot {\mathbf {r} }}\times \mathbf {H} =\alpha \mathbf {u} +\mathbf {c} }

where c is a constant vector. Dotting this with r yields an interesting result: πŸ‘ {\displaystyle \mathbf {r} \cdot ({\dot {\mathbf {r} }}\times \mathbf {H} )=\mathbf {r} \cdot (\alpha \mathbf {u} +\mathbf {c} )=\alpha \mathbf {r} \cdot \mathbf {u} +\mathbf {r} \cdot \mathbf {c} =\alpha r(\mathbf {u} \cdot \mathbf {u} )+rc\cos(\theta )=r(\alpha +c\cos(\theta ))}
where πŸ‘ {\displaystyle \theta }
is the angle between πŸ‘ {\displaystyle \mathbf {r} }
and πŸ‘ {\displaystyle \mathbf {c} }
. Solving for r : πŸ‘ {\displaystyle r={\frac {\mathbf {r} \cdot ({\dot {\mathbf {r} }}\times \mathbf {H} )}{\alpha +c\cos(\theta )}}={\frac {(\mathbf {r} \times {\dot {\mathbf {r} }})\cdot \mathbf {H} }{\alpha +c\cos(\theta )}}={\frac {|\mathbf {H} |^{2}}{\alpha +c\cos(\theta )}}={\frac {|\mathbf {H} |^{2}/\alpha }{1+(c/\alpha )\cos(\theta )}}.}

Notice that πŸ‘ {\displaystyle (r,\theta )}
are effectively the polar coordinates of the vector function. Making the substitutions πŸ‘ {\displaystyle p={\tfrac {|\mathbf {H} |^{2}}{\alpha }}}
and πŸ‘ {\displaystyle e={\tfrac {c}{\alpha }}}
, we again arrive at the equation

πŸ‘ {\displaystyle r={\frac {p}{1+e\cdot \cos \theta }}}
13

This is the equation in polar coordinates for a conic section with origin in a focal point. The argument πŸ‘ {\displaystyle \theta }
is called "true anomaly".

Eccentricity Vector

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Notice also that, since πŸ‘ {\displaystyle \theta }
is the angle between the position vector πŸ‘ {\displaystyle \mathbf {r} }
and the integration constant πŸ‘ {\displaystyle \mathbf {c} }
, the vector πŸ‘ {\displaystyle \mathbf {c} }
must be pointing in the direction of the periapsis of the orbit. We can then define the eccentricity vector associated with the orbit as: πŸ‘ {\displaystyle \mathbf {e} \triangleq {\frac {\mathbf {c} }{\alpha }}={\frac {{\dot {\mathbf {r} }}\times \mathbf {H} }{\alpha }}-\mathbf {u} ={\frac {\mathbf {v} \times \mathbf {H} }{\alpha }}-{\frac {\mathbf {r} }{r}}={\frac {\mathbf {v} \times (\mathbf {r} \times \mathbf {v} )}{\alpha }}-{\frac {\mathbf {r} }{r}}}

where πŸ‘ {\displaystyle \mathbf {H} =\mathbf {r} \times {\dot {\mathbf {r} }}=\mathbf {r} \times \mathbf {v} }
is the constant angular momentum vector of the orbit, and πŸ‘ {\displaystyle \mathbf {v} }
is the velocity vector associated with the position vector πŸ‘ {\displaystyle \mathbf {r} }
.

Obviously, the eccentricity vector, having the same direction as the integration constant πŸ‘ {\displaystyle \mathbf {c} }
, also points to the direction of the periapsis of the orbit, and it has the magnitude of orbital eccentricity. This makes it very useful in orbit determination (OD) for the orbital elements of an orbit when a state vector [πŸ‘ {\displaystyle \mathbf {r} ,\mathbf {\dot {r}} }
] or [πŸ‘ {\displaystyle \mathbf {r} ,\mathbf {v} }
] is known.

Properties of trajectory equation

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For πŸ‘ {\displaystyle e=0}
this is a circle with radius p.

For πŸ‘ {\displaystyle 0<e<1,}
this is an ellipse with

πŸ‘ {\displaystyle a={\frac {p}{1-e^{2}}}}
14
πŸ‘ {\displaystyle b={\frac {p}{\sqrt {1-e^{2}}}}=a\cdot {\sqrt {1-e^{2}}}}
15

For πŸ‘ {\displaystyle e=1}
this is a parabola with focal length πŸ‘ {\displaystyle {\tfrac {p}{2}}}

For πŸ‘ {\displaystyle e>1}
this is a hyperbola with

πŸ‘ {\displaystyle a={\frac {p}{e^{2}-1}}}
16
πŸ‘ {\displaystyle b={\frac {p}{\sqrt {e^{2}-1}}}=a\cdot {\sqrt {e^{2}-1}}}
17

The following image illustrates a circle (grey), an ellipse (red), a parabola (green) and a hyperbola (blue)

πŸ‘ Image
A diagram of the various forms of the Kepler Orbit and their eccentricities. Blue is a hyperbolic trajectory (e > 1). Green is a parabolic trajectory (e = 1). Red is an elliptical orbit (0 < e < 1). Grey is a circular orbit (e = 0).

The point on the horizontal line going out to the right from the focal point is the point with πŸ‘ {\displaystyle \theta =0}
for which the distance to the focus takes the minimal value πŸ‘ {\displaystyle {\tfrac {p}{1+e}},}
the pericentre. For the ellipse there is also an apocentre for which the distance to the focus takes the maximal value πŸ‘ {\displaystyle {\tfrac {p}{1-e}}.}
For the hyperbola the range for πŸ‘ {\displaystyle \theta }
is πŸ‘ {\displaystyle -\cos ^{-1}\left(-{\frac {1}{e}}\right)<\theta <\cos ^{-1}\left(-{\frac {1}{e}}\right)}
and for a parabola the range is πŸ‘ {\displaystyle -\pi <\theta <\pi }

Using the chain rule for differentiation (5), the equation (2) and the definition of p as πŸ‘ {\displaystyle {\frac {H^{2}}{\alpha }}}
one gets that the radial velocity component is

πŸ‘ {\displaystyle V_{r}={\dot {r}}={\frac {H}{p}}e\sin \theta ={\sqrt {\frac {\alpha }{p}}}e\sin \theta }
18

and that the tangential component (velocity component perpendicular to πŸ‘ {\displaystyle V_{r}}
) is

πŸ‘ {\displaystyle V_{t}=r\cdot {\dot {\theta }}={\frac {H}{r}}={\sqrt {\frac {\alpha }{p}}}\cdot (1+e\cdot \cos \theta )}
19

The connection between the polar argument πŸ‘ {\displaystyle \theta }
and time t is slightly different for elliptic and hyperbolic orbits.

For an elliptic orbit one switches to the "eccentric anomaly" E for which

πŸ‘ {\displaystyle x=a\cdot (\cos E-e)}
20
πŸ‘ {\displaystyle y=b\cdot \sin E}
21

and consequently

πŸ‘ {\displaystyle {\dot {x}}=-a\cdot \sin E\cdot {\dot {E}}}
22
πŸ‘ {\displaystyle {\dot {y}}=b\cdot \cos E\cdot {\dot {E}}}
23

and the angular momentum H is

πŸ‘ {\displaystyle H=x\cdot {\dot {y}}-y\cdot {\dot {x}}=a\cdot b\cdot (1-e\cdot \cos E)\cdot {\dot {E}}}
24

Integrating with respect to time t gives

πŸ‘ {\displaystyle H\cdot t=a\cdot b\cdot (E-e\cdot \sin E)}
25

under the assumption that time πŸ‘ {\displaystyle t=0}
is selected such that the integration constant is zero.

As by definition of p one has

πŸ‘ {\displaystyle H={\sqrt {\alpha \cdot p}}}
26

this can be written

πŸ‘ {\displaystyle t=a\cdot {\sqrt {\frac {a}{\alpha }}}(E-e\cdot \sin E)}
27

For a hyperbolic orbit one uses the hyperbolic functions for the parameterisation

πŸ‘ {\displaystyle x=a\cdot (e-\cosh E)}
28
πŸ‘ {\displaystyle y=b\cdot \sinh E}
29

for which one has

πŸ‘ {\displaystyle {\dot {x}}=-a\cdot \sinh E\cdot {\dot {E}}}
30
πŸ‘ {\displaystyle {\dot {y}}=b\cdot \cosh E\cdot {\dot {E}}}
31

and the angular momentum H is

πŸ‘ {\displaystyle H=x\cdot {\dot {y}}-y\cdot {\dot {x}}=a\cdot b\cdot (e\cdot \cosh E-1)\cdot {\dot {E}}}
32

Integrating with respect to time t gets

πŸ‘ {\displaystyle H\cdot t=a\cdot b\cdot (e\cdot \sinh E-E)}
33

i.e.

πŸ‘ {\displaystyle t=a\cdot {\sqrt {\frac {a}{\alpha }}}(e\cdot \sinh E-E)}
34

To find what time t that corresponds to a certain true anomaly πŸ‘ {\displaystyle \theta }
one computes corresponding parameter E connected to time with relation (27) for an elliptic and with relation (34) for a hyperbolic orbit.

Note that the relations (27) and (34) define a mapping between the ranges πŸ‘ {\displaystyle \left[-\infty <t<\infty \right]\longleftrightarrow \left[-\infty <E<\infty \right]}

Some additional formulae

[edit]

Elliptic orbit

[edit]

For an elliptic orbit one gets from (20) and (21) that

πŸ‘ {\displaystyle r=a\cdot (1-e\cos E)}
35

and therefore that

πŸ‘ {\displaystyle \cos \theta ={\frac {x}{r}}={\frac {\cos E-e}{1-e\cos E}}}
36

From (36) then follows that πŸ‘ {\displaystyle \tan ^{2}{\frac {\theta }{2}}={\frac {1-\cos \theta }{1+\cos \theta }}={\frac {1-{\frac {\cos E-e}{1-e\cos E}}}{1+{\frac {\cos E-e}{1-e\cos E}}}}={\frac {1-e\cos E-\cos E+e}{1-e\cos E+\cos E-e}}={\frac {1+e}{1-e}}\cdot {\frac {1-\cos E}{1+\cos E}}={\frac {1+e}{1-e}}\cdot \tan ^{2}{\frac {E}{2}}}

From the geometrical construction defining the eccentric anomaly it is clear that the vectors πŸ‘ {\displaystyle (\cos E,\sin E)}
and πŸ‘ {\displaystyle (\cos \theta ,\sin \theta )}
are on the same side of the x-axis. From this then follows that the vectors πŸ‘ {\displaystyle \left(\cos {\tfrac {E}{2}},\sin {\tfrac {E}{2}}\right)}
and πŸ‘ {\displaystyle \left(\cos {\tfrac {\theta }{2}},\sin {\tfrac {\theta }{2}}\right)}
are in the same quadrant. One therefore has that

πŸ‘ {\displaystyle \tan {\frac {\theta }{2}}={\sqrt {\frac {1+e}{1-e}}}\cdot \tan {\frac {E}{2}}}
37

and that

πŸ‘ {\displaystyle \theta =2\cdot \arg \left({\sqrt {1-e}}\cdot \cos {\frac {E}{2}},{\sqrt {1+e}}\cdot \sin {\frac {E}{2}}\right)+n\cdot 2\pi }
38
πŸ‘ {\displaystyle E=2\cdot \arg \left({\sqrt {1+e}}\cdot \cos {\frac {\theta }{2}},{\sqrt {1-e}}\cdot \sin {\frac {\theta }{2}}\right)+n\cdot 2\pi }
39

where "πŸ‘ {\displaystyle \arg(x,y)}
" is the polar argument of the vector πŸ‘ {\displaystyle (x,y)}
and n is selected such that πŸ‘ {\displaystyle |E-\theta |<\pi }

For the numerical computation of πŸ‘ {\displaystyle \arg(x,y)}
the standard function ATAN2(y,x) (or in double precision DATAN2(y,x)) available in for example the programming language FORTRAN can be used.

Note that this is a mapping between the ranges πŸ‘ {\displaystyle \left[-\infty <\theta <\infty \right]\longleftrightarrow \left[-\infty <E<\infty \right]}

Hyperbolic orbit

[edit]

For a hyperbolic orbit one gets from (28) and (29) that

πŸ‘ {\displaystyle r=a\cdot (e\cdot \cosh E-1)}
40

and therefore that

πŸ‘ {\displaystyle \cos \theta ={\frac {x}{r}}={\frac {e-\cosh E}{e\cdot \cosh E-1}}}
41

As πŸ‘ {\displaystyle \tan ^{2}{\frac {\theta }{2}}={\frac {1-\cos \theta }{1+\cos \theta }}={\frac {1-{\frac {e-\cosh E}{e\cdot \cosh E-1}}}{1+{\frac {e-\cosh E}{e\cdot \cosh E-1}}}}={\frac {e\cdot \cosh E-e+\cosh E}{e\cdot \cosh E+e-\cosh E}}={\frac {e+1}{e-1}}\cdot {\frac {\cosh E-1}{\cosh E+1}}={\frac {e+1}{e-1}}\cdot \tanh ^{2}{\frac {E}{2}}}
and as πŸ‘ {\displaystyle \tan {\frac {\theta }{2}}}
and πŸ‘ {\displaystyle \tanh {\frac {E}{2}}}
have the same sign it follows that

πŸ‘ {\displaystyle \tan {\frac {\theta }{2}}={\sqrt {\frac {e+1}{e-1}}}\cdot \tanh {\frac {E}{2}}}
42

This relation is convenient for passing between "true anomaly" and the parameter E, the latter being connected to time through relation (34). Note that this is a mapping between the ranges πŸ‘ {\displaystyle \left[-\cos ^{-1}\left(-{\frac {1}{e}}\right)<\theta <\cos ^{-1}\left(-{\frac {1}{e}}\right)\right]\longleftrightarrow \left[-\infty <E<\infty \right]}
and that πŸ‘ {\displaystyle {\tfrac {E}{2}}}
can be computed using the relation πŸ‘ {\displaystyle \tanh ^{-1}x={\frac {1}{2}}\ln \left({\frac {1+x}{1-x}}\right)}

From relation (27) follows that the orbital period P for an elliptic orbit is

πŸ‘ {\displaystyle P=2\pi a\cdot {\sqrt {\frac {a}{\alpha }}}}
43

As the potential energy corresponding to the force field of relation (1) is πŸ‘ {\displaystyle -{\frac {\alpha }{r}}}
it follows from (13), (14), (18) and (19) that the sum of the kinetic and the potential energy πŸ‘ {\displaystyle {\frac {{V_{r}}^{2}+{V_{t}}^{2}}{2}}-{\frac {\alpha }{r}}}
for an elliptic orbit is

πŸ‘ {\displaystyle -{\frac {\alpha }{2a}}}
44

and from (13), (16), (18) and (19) that the sum of the kinetic and the potential energy for a hyperbolic orbit is

πŸ‘ {\displaystyle {\frac {\alpha }{2a}}}
45

Relative the inertial coordinate system πŸ‘ {\displaystyle {\hat {x}},{\hat {y}}}
in the orbital plane with πŸ‘ {\displaystyle {\hat {x}}}
towards pericentre one gets from (18) and (19) that the velocity components are

πŸ‘ {\displaystyle V_{x}=V_{r}\cos \theta -V_{t}\sin \theta =-{\sqrt {\frac {\alpha }{p}}}\cdot \sin \theta }
46
πŸ‘ {\displaystyle V_{y}=V_{r}\sin \theta +V_{t}\cos \theta ={\sqrt {\frac {\alpha }{p}}}\cdot (e+\cos \theta )}
47

The equation of the center relates mean anomaly to true anomaly for elliptical orbits, for small numerical eccentricity.

Parabolic orbit

[edit]

For a parabolic orbit, let πŸ‘ {\displaystyle e=1}
and πŸ‘ {\displaystyle p=2f}
in (13) so that the orbit in polar coordinates is

πŸ‘ {\displaystyle r={\frac {2\,f}{1+\cos \theta }}}

This gives the orbit in cartesian coordinates as

πŸ‘ {\displaystyle y^{2}=-4\,f\,(x-f)}

This is a parabola[4] with focal length πŸ‘ {\displaystyle f}
and focus at the origin. The parabola extends to minus infinity in πŸ‘ {\displaystyle x}
. In terms of the true anomaly πŸ‘ {\displaystyle \theta }
and the periapsis distance πŸ‘ {\displaystyle q=f}
, the equations for the x and y coordinates are[5]

πŸ‘ {\displaystyle {\begin{aligned}x&=q\,{\Big (}1-\tan ^{2}{\Big (}{\frac {\theta }{2}}{\Big )}{\Big )}\\y&=2\,q\,\tan {\Big (}{\frac {\theta }{2}}{\Big )}\end{aligned}}}

As required

πŸ‘ {\displaystyle {\begin{aligned}{\frac {y}{x}}&=\tan \theta \\r&={\sqrt {x^{2}+y^{2}}}=q\,\sec ^{2}{\Big (}{\frac {\theta }{2}}{\Big )}={\frac {2\,q}{1+\cos \theta }}\end{aligned}}}

The area πŸ‘ {\displaystyle S(\theta )}
swept out from the periapsis by the radius vector is

πŸ‘ {\displaystyle {\begin{aligned}S(\theta )=\int \limits _{0}^{\theta }{\frac {1}{2}}r^{2}\,d\theta \,&=\int \limits _{0}^{\theta }{\frac {1}{2}}\,q^{2}\,\sec ^{4}{\Big (}{\frac {\theta }{2}}{\Big )}\,d\,\theta =\int \limits _{0}^{\theta }q^{2}\,{\Big (}1+\tan ^{2}{\Big (}{\frac {\theta }{2}}{\Big )}{\Big )}\;d\,\tan {\Big (}{\frac {\theta }{2}}{\Big )}\\&=\,q^{2}{\Big (}\tan {\Big (}{\frac {\theta }{2}}{\Big )}+{\frac {1}{3}}\,\tan ^{3}{\Big (}{\frac {\theta }{2}}{\Big )}{\Big )}\end{aligned}}}

By Kepler's Second Law of equal areas in equal times this must be proportional to the time πŸ‘ {\displaystyle t}
since the periapsis. Let πŸ‘ {\displaystyle q^{2}K}
be the constant of proportionality so that

πŸ‘ {\displaystyle S(\theta )=q^{2}\,K\,t}
πŸ‘ {\displaystyle }

Differentiation with respect to t gives

πŸ‘ {\displaystyle {\frac {d\,\theta }{d\,t}}=2\,K\,\cos ^{4}{\Big (}{\frac {\theta }{2}}{\Big )}}

By conservation of energy, the sum of the kinetic energy πŸ‘ {\displaystyle KE}
and potential energy πŸ‘ {\displaystyle PE}
must not depend upon πŸ‘ {\displaystyle \theta }
. These are given by

πŸ‘ {\displaystyle {\begin{aligned}KE&={\frac {1}{2}}({\dot {x}}^{2}+{\dot {y}}^{2})={\frac {q^{2}}{2}}\,\sec ^{6}{\Big (}{\frac {\theta }{2}}{\Big )}\,{\Big (}{\frac {d\,\theta }{d\,t}}{\Big )}^{2}=2\,q^{2}\,K^{2}\,\cos ^{2}{\Big (}{\frac {\theta }{2}}{\Big )}\\PE&={\frac {-G\,M}{r}}={\frac {-G\,M}{q}}\,\cos ^{2}{\Big (}{\frac {\theta }{2}}{\Big )}\end{aligned}}}

For πŸ‘ {\displaystyle KE+PE}
to be independent of πŸ‘ {\displaystyle \theta }
, it must be that

πŸ‘ {\displaystyle K={\sqrt {\frac {G\,M}{2\,q^{3}}}}}

This makes the total energy be zero, as expected. Then[6]

πŸ‘ {\displaystyle \tan {\Big (}{\frac {\theta }{2}}{\Big )}+{\frac {1}{3}}\,\tan ^{3}{\Big (}{\frac {\theta }{2}}{\Big )}={\sqrt {\frac {G\,M}{2\,q^{3}}}}\,t}

This is Barker's equation and can be solved exactly for πŸ‘ {\displaystyle \theta (t)}
. Solve this cubic equation by letting

πŸ‘ {\displaystyle \tan {\Big (}{\frac {\theta }{2}}{\Big )}=B-{\frac {1}{B}}}

to obtain

πŸ‘ {\displaystyle B^{3}-{\frac {1}{B^{3}}}\,=2\,A\;{\text{for}}\;A={\frac {3}{2}}\,{\sqrt {\frac {G\,M}{2\,q^{3}}}}\,t}

This is a quadratic equation in πŸ‘ {\displaystyle B^{3}}
which has the solution

πŸ‘ {\displaystyle B={\sqrt[{3}]{A+{\sqrt {A^{2}+1}}}}}

Determination of the Kepler orbit that corresponds to a given initial state

[edit]

This is the "initial value problem" for the differential equation (1) which is a first order equation for the 6-dimensional "state vector" πŸ‘ {\displaystyle (\mathbf {r} ,\mathbf {v} )}
when written as

πŸ‘ {\displaystyle {\dot {\mathbf {v} }}=-\alpha \cdot {\frac {\hat {\mathbf {r} }}{r^{2}}}}
48
πŸ‘ {\displaystyle {\dot {\mathbf {r} }}=\mathbf {v} }
49

For any values for the initial "state vector" πŸ‘ {\displaystyle (\mathbf {r} _{0},\mathbf {v} _{0})}
the Kepler orbit corresponding to the solution of this initial value problem can be found with the following algorithm:

Define the orthogonal unit vectors πŸ‘ {\displaystyle ({\hat {\mathbf {r} }},{\hat {\mathbf {t} }})}
through

πŸ‘ {\displaystyle \mathbf {r} _{0}=r{\hat {\mathbf {r} }}}
50
πŸ‘ {\displaystyle \mathbf {v} _{0}=V_{r}{\hat {\mathbf {r} }}+V_{t}{\hat {\mathbf {t} }}}
51

with πŸ‘ {\displaystyle r>0}
and πŸ‘ {\displaystyle V_{t}>0}

From (13), (18) and (19) follows that by setting

πŸ‘ {\displaystyle p={\frac {{(r\cdot V_{t})}^{2}}{\alpha }}}
52

and by defining πŸ‘ {\displaystyle e\geq 0}
and πŸ‘ {\displaystyle \theta }
such that

πŸ‘ {\displaystyle e\cos \theta ={\frac {V_{t}}{V_{0}}}-1}
53
πŸ‘ {\displaystyle e\sin \theta ={\frac {V_{r}}{V_{0}}}}
54

where

πŸ‘ {\displaystyle V_{0}={\sqrt {\frac {\alpha }{p}}}}
55

one gets a Kepler orbit that for true anomaly πŸ‘ {\displaystyle \theta }
has the same r, πŸ‘ {\displaystyle V_{r}}
and πŸ‘ {\displaystyle V_{t}}
values as those defined by (50) and (51).

If this Kepler orbit then also has the same πŸ‘ {\displaystyle ({\hat {\mathbf {r} }},{\hat {\mathbf {t} }})}
vectors for this true anomaly πŸ‘ {\displaystyle \theta }
as the ones defined by (50) and (51) the state vector πŸ‘ {\displaystyle (\mathbf {r} ,\mathbf {v} )}
of the Kepler orbit takes the desired values πŸ‘ {\displaystyle (\mathbf {r} _{0},\mathbf {v} _{0})}
for true anomaly πŸ‘ {\displaystyle \theta }
.

The standard inertially fixed coordinate system πŸ‘ {\displaystyle ({\hat {\mathbf {x} }},{\hat {\mathbf {y} }})}
in the orbital plane (with πŸ‘ {\displaystyle {\hat {\mathbf {x} }}}
directed from the centre of the homogeneous sphere to the pericentre) defining the orientation of the conical section (ellipse, parabola or hyperbola) can then be determined with the relation

πŸ‘ {\displaystyle {\hat {\mathbf {x} }}=\cos \theta {\hat {\mathbf {r} }}-\sin \theta {\hat {\mathbf {t} }}}
56
πŸ‘ {\displaystyle {\hat {\mathbf {y} }}=\sin \theta {\hat {\mathbf {r} }}+\cos \theta {\hat {\mathbf {t} }}}
57

Note that the relations (53) and (54) has a singularity when πŸ‘ {\displaystyle V_{r}=0}
and πŸ‘ {\displaystyle V_{t}=V_{0}={\sqrt {\frac {\alpha }{p}}}={\sqrt {\frac {\alpha }{\frac {{(r\cdot V_{t})}^{2}}{\alpha }}}}}
i.e.

πŸ‘ {\displaystyle V_{t}={\sqrt {\frac {\alpha }{r}}}}
58

which is the case that it is a circular orbit that is fitting the initial state πŸ‘ {\displaystyle (\mathbf {r} _{0},\mathbf {v} _{0})}

The osculating Kepler orbit

[edit]

For any state vector πŸ‘ {\displaystyle (\mathbf {r} ,\mathbf {v} )}
the Kepler orbit corresponding to this state can be computed with the algorithm defined above. First the parameters πŸ‘ {\displaystyle p,e,\theta }
are determined from πŸ‘ {\displaystyle r,V_{r},V_{t}}
and then the orthogonal unit vectors in the orbital plane πŸ‘ {\displaystyle {\hat {x}},{\hat {y}}}
using the relations (56) and (57).

If now the equation of motion is

πŸ‘ {\displaystyle {\ddot {\mathbf {r} }}=\mathbf {F} (\mathbf {r} ,{\dot {\mathbf {r} }},t)}
59

where πŸ‘ {\displaystyle \mathbf {F} (\mathbf {r} ,{\dot {\mathbf {r} }},t)}
is a function other than πŸ‘ {\displaystyle -\alpha {\frac {\mathbf {r} }{r^{2}}}}
the resulting parameters πŸ‘ {\displaystyle p}
, πŸ‘ {\displaystyle e}
, πŸ‘ {\displaystyle \theta }
, πŸ‘ {\displaystyle {\hat {\mathbf {x} }}}
, πŸ‘ {\displaystyle {\hat {\mathbf {y} }}}
defined by πŸ‘ {\displaystyle \mathbf {r} ,{\dot {\mathbf {r} }}}
will all vary with time as opposed to the case of a Kepler orbit for which only the parameter πŸ‘ {\displaystyle \theta }
will vary.

The Kepler orbit computed in this way having the same "state vector" as the solution to the "equation of motion" (59) at time t is said to be "osculating" at this time.

This concept is for example useful in case πŸ‘ {\displaystyle \mathbf {F} (\mathbf {r} ,{\dot {\mathbf {r} }},t)=-\alpha {\frac {\hat {\mathbf {r} }}{r^{2}}}+\mathbf {f} (\mathbf {r} ,{\dot {\mathbf {r} }},t)}
where πŸ‘ {\displaystyle \mathbf {f} (\mathbf {r} ,{\dot {\mathbf {r} }},t)}

is a small "perturbing force" due to for example a faint gravitational pull from other celestial bodies. The parameters of the osculating Kepler orbit will then only slowly change and the osculating Kepler orbit is a good approximation to the real orbit for a considerable time period before and after the time of osculation.

This concept can also be useful for a rocket during powered flight as it then tells which Kepler orbit the rocket would continue in case the thrust is switched off.

For a "close to circular" orbit the concept "eccentricity vector" defined as πŸ‘ {\displaystyle \mathbf {e} =e{\hat {\mathbf {x} }}}
is useful. From (53), (54) and (56) follows that

πŸ‘ {\displaystyle \mathbf {e} ={\frac {(V_{t}-V_{0}){\hat {\mathbf {r} }}-V_{r}{\hat {\mathbf {t} }}}{V_{0}}}}
60

i.e. πŸ‘ {\displaystyle \mathbf {e} }
is a smooth differentiable function of the state vector πŸ‘ {\displaystyle (\mathbf {r} ,\mathbf {v} )}
also if this state corresponds to a circular orbit.

See also

[edit]

References

[edit]
  1. ^ Copernicus. pp 513–514
  2. ^ Bate, Mueller, White. pp 177–181
  3. ^ "NASA website". Archived from the original on 16 February 2011. Retrieved 12 August 2012.
  4. ^ Brannan, David A; Esplen, Mathew F; Gray, Jeremy J (2012). Geometry, 2nd Edition. Cambridge: Cambridge University Press. p. 12. ISBN 978-1-107-64783-1.
  5. ^ Montenbruck, Oliver; Pfleger, Thomas (2003). Astronomy on the Personal Computer. Berlin Heidelberg New York: Springer. p. 64. ISBN 978-3-662-11187-1.
  6. ^ Montenbruck, Oliver; Pfleger, Thomas. Astronomy on the Personal Computer. p. 64.

Further reading

[edit]
  • El'Yasberg "Theory of flight of artificial earth satellites", Israel program for Scientific Translations (1967)
  • Bate, Roger; Mueller, Donald; White, Jerry (1971). Fundamentals of Astrodynamics. Dover Publications, Inc., New York. ISBN 0-486-60061-0.
  • Copernicus, Nicolaus (1952), "Book I, Chapter 4, The Movement of the Celestial Bodies Is Regular, Circular, and Everlasting-Or Else Compounded of Circular Movements", On the Revolutions of the Heavenly Spheres, Great Books of the Western World, vol. 16, translated by Charles Glenn Wallis, Chicago: William Benton, pp. 497–838

External links

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