C# | Math.Abs() Method | Set - 2

C# | Math.Abs() Method | Set – 1 In C#, Abs() is a Math class method which is used to return the absolute value of a specified number. This method can be overload by passing the different type of parameters to it. There are total 7 methods in its overload list.

1. Math.Abs(Decimal)
2. Math.Abs(Double)
3. Math.Abs(Int16)
4. Math.Abs(Int32)
5. Math.Abs(Int64)
6. Math.Abs(SByte)
7. Math.Abs(Single)

Math.Abs(Int64)

This method is used to return the absolute value of a 64-bit signed integer. Syntax:

public static long Abs (long val);

Parameter:

val: It is the required number which is greater than Int64.MinValue, but less than or equal to Int64.MaxValue of type System.Int64.

Return Type: It returns a 64-bit signed integer say r, such that 0 ≤ r ≤ Int64.MaxValue. Exception: This method will give OverflowException if the value of val is equals to Int64.MinValue. Example: Output:

Absolute value of 9223372036854775807 = 9223372036854775807
Absolute value of 78345482 = 78345482
Absolute value of -4687985 = 4687985
Absolute value of 0 = 0

Math.Abs(SByte)

This method is used to return the absolute value of an 8-bit signed integer. Syntax:

public static sbyte Abs (sbyte val);

Parameter:

val: It is the required number which is greater than SByte.MinValue, but less than or equal to SByte.MaxValue of type System.SByte.

Return Type: It returns a 8-bit signed integer say r, such that 0 ≤ r ≤ SByte.MaxValue. Exception: This method will give OverflowException if the value of val is equals to SByte.MinValue. Example: Output:

Absolute value of 127 = 127
Absolute value of 45 = 45
Absolute value of -41 = 41
Absolute value of 0 = 0

Math.Abs(Single)

This method is used to return the absolute value of a single-precision floating-point number. Syntax:

public static float Abs (float val);

Parameter:

val: It is the required number which is greater than or equal to Single.MinValue, but less than or equal to MaxValue of type System.Single.

Return Type: It returns a single-precision floating-point number say r, such that 0 ≤ r ≤ Single.MaxValue. Note:
• If val is equal to NegativeInfinity or PositiveInfinity, the return value will be PositiveInfinity.
• If the val is equal to NaN then return value will be NaN.
Example:

Output:

Absolute value of -3.402823E+38 = 3.402823E+38
Absolute value of 127.58 = 127.58
Absolute value of 0 = 0
Absolute value of 7.55648E+13 = 7.55648E+13
Absolute value of NaN = NaN
Absolute value of 3.402823E+38 = 3.402823E+38

Reference: https://learn.microsoft.com/en-us/dotnet/api/system.math.abs?view=netframework-4.7.2