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Decimal.Round() Method in C# | Set - 1

Last Updated : 11 Jul, 2025
Decimal.Round Method is used to round a value to the nearest integer or a specified number of decimal places. There are 4 methods in the overload list of this method as follows:
  • Round(Decimal) Method
  • Round(Decimal, Int32) Method
  • Round(Decimal, MidpointRounding) Method
  • Round(Decimal, Int32, MidpointRounding) Method
Here, we will discuss the first two methods.

Decimal.Round(Decimal) Method

This method is used to round a decimal value to the nearest integer.
Syntax: public static decimal Round (decimal d); Here, it takes a decimal number to round. Return Value: This method returns the integer which is nearest to the d parameter. If d is halfway between two integers, one of which is even and the other odd, the even number is returned. Exceptions: This method throws OverflowException if the result is outside the range of a Decimal value.
Below programs illustrate the use of Decimal.Round(Decimal) Method: Example 1: Output:
Rounded value is 184467440737096
Example 2: For OverflowException Compile-Time Errors:
prog.cs(15,51): error CS0594: Floating-point constant is outside the range of type `decimal'

Round(Decimal, Int32) Method

This method is used to round a Decimal value to a specified number of decimal places.
Syntax: public static decimal Round (decimal d, int decimals); Parameters: d: It is a decimal number which is to be rounded. decimals: It is a value from 0 to 28 that specifies the number of decimal places to round to.
Return Value: This method returns the decimal number equivalent to d rounded to decimals number of decimal places. Exception: This method throws ArgumentOutOfRangeException if decimals is not a value from 0 to 28. Below programs illustrate the use of Decimal.Round(Decimal, Int32) Method: Example 1: Output:
Rounded value is 7922816251426433759354.3950
Example 2: For ArgumentOutOfRangeException
Output:
Decimal place is not within bound
Exception Thrown: System.ArgumentOutOfRangeException
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