A 30-60-90 triangle is a special type of right triangle with one angle measuring 30Β°, another 60Β°, and the third angle (the right angle) measuring 90Β°. The 30-60-90 triangle is called a special right triangle as the angles of this triangle are in a unique ratio of 1:2:3. Here, a right triangle means being any triangle that contains a 90Β° angle.
The below figure represents the 30-60-90 triangle with β A = 60Β°, β B = 90Β°and β C = 30Β°. The 30-60-90 is pronounced as "thirty - sixty - ninety".
A 30Β°β60Β°β90Β° triangle is a special type of right triangle with fixed angle measures. In the below-given 30-60-90 triangle ABC, β C = 30Β°,β A = 60Β°, and β B = 90Β°. We can understand the relationship between each of the sides from the following definitions:
The side opposite to the angle 30Β° holds the smallest value and let it be "a" cm. Another side representing opposite to the opposite angle of 60Β° holds the moderate value, and it is "aβ3" cm. Lastly, the side opposite to the angle 90Β° holds the largest value, and it is "2a" cm.
Let's first consider the equilateral triangle (all sides being equal and making an angle of 60Β° at vertices) as shown in the figure. If we draw a line from one of the vertexes (say A) to the other side (say BC). Then the other side i.e., BC is divided into 2 equal halves (each part with a/2) and makes an angle of 90Β°. Let the dividing point or the midpoint of BC be D. Due to the line that is drawn the angle at the vertex A which is 60Β° will also be divided equally and each part holds 30Β°.
Now look at the half part of the figure which is triangle ABD, it resembles a 30-60-90 triangle with sides AB = a cm, BD = a/2 cm, AD = unknown (say x cm)
To find the value of AD let's use the Pythagoras theorem, which states that "In a right-angled triangle, the square of the hypotenuse side (longest side) is equal to the sum of squares of the other two sidesβ, from the figure AB is the hypotenuse, BD and AD are other 2 sides.
Therefore,
AB2 = BD2 + AD2
a2 = (a/2)2 + x2
x2 = a2 - (a/2)2
x = β3a/2 cm (AD)
The ratio of the sides that are opposite to the angles 30-60-90 will be a/2: β3a/2: a β 1:β3:2 (taking as common and neglecting it and multiplying with 2)
This ratio 1:β3:2 is known as the 30-60-90 formula
30-60-90 Triangle Rule
A 30-60-90 triangle is a special right triangle with angles of 30Β°, 60Β°, and 90Β°. The sides of such a triangle always follow the ratio:
Shortest side (opposite 30Β°) : Side opposite 60Β° : Hypotenuse = 1 : β3 : 2
How to Find the Sides
Below is a table showing how to calculate all sides if you know any one side:
To find the third side i.e., x from the 30-60-90 formula 1:β3:2 x β β3a
x β 20 Γ β3 cm.
x = 20β3cm
Question 2: The shortest side of the 30-60-90 is 40cm, find the area of the triangle?
Solution:
In a 30-60-90 triangle, the sides are in a specific ratio. The side opposite the 30-degree angle is half the length of the hypotenuse, and the side opposite the 60-degree angle is β3/2 times the length of the hypotenuse.
Given that the shortest side is 40 cm, we can use this information to find the lengths of the other sides.
Let ( x ) be the length of the shortest side (opposite the 30-degree angle), then the lengths of the other sides are:
- The length of the medium side (opposite the 60-degree angle) is xβ3
- The length of the longest side (the hypotenuse) is ( 2x ).
We're given that the shortest side is 40 cm. So, ( x = 40 ) cm.
- The length of the medium side is 40β3 cm.
- The length of the longest side (hypotenuse) is ( 2 x 40 = 80 ) cm.
Now, to find the area of the triangle, we can use the formula:
Area = 1/2 x base x height
In a 30-60-90 triangle, the base (shortest side) is opposite the 30-degree angle, and the height is opposite the 60-degree angle.
So, the area is: Area = 1/2 x 40 x 40β3 Area = 20 x 40β3 Area = 800β3
Thus, the area of the triangle is 800β3 square centimeters.
Question 3: The longest side of the 30-60-90 is 120cm, find the area of the triangle?
Solution:
Given the longest side is 120cm i.e., 2a = 120 cm. Short leg : Long leg : Hypotenuse= 1 : β3 β:2 Let a be the shorter leg Therefore, a = 60 cm. The longer leg is = aβ3 β= 60β3 β The area of the triangle is A = (1/2) Γ b Γ h = (1/2) Γ 60 Γ 60β3 β= 1800β3 βcm2
Therefore Area = 1800β3 βcm2
Question 4: The moderate side of the 30-60-90 is 12β3cm, find the area of the triangle?
Solution:
Given the moderate side is 120cm i.e., aβ3 = 12β3 cm. Therefore, a = 12 cm. The hypoteuse is 2x The area of the triangle is A = (1/2) Γ b Γ h = (1/2) Γ 12 Γ 12β3 β β= 72β3 βcm2
Therefore Area = 72β3 βcm2
Question 5: The shortest side of the triangle is 90 cm, find the longest side?
Solution:
Given the shortest side of 30-60-90 is 90 cm. From the 30-60-90 formula the shortest and longest sides are in the ratio 1 : 2 β x : 2x Given x = 90 2x = ?
Therefore, 2x = 2 Γ 90 = 180 cm.
Question 6: The longest side of the triangle is 20cm, find the intermediate side length?
Solution:
Given the longest side of 30-60-90 is 20 cm. From 30-60-90 formula the longest and intermediate sides are in the ratio 2:β3 β 2x :β3 x Given 2x = 20 x = 10