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ASA Congruence Rule: ASA stands for Angle-Side-Angle. It is one of the congruence tests used to test the congruence of two triangles. Other than ASA there are 4 more congruence rules i.e., SSS, SAS, AAS, and RHS.
Condition of Congruency of Two Triangles: Two triangles are said to be congruent if two angles and the included side of one triangle are equal to two angles and the included side of another triangle.
In this article, we will learn about the ASA Congruence Rule including its proof, applications, and examples related to it.
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Congruence is a term used in mathematics to describe a relationship between geometric figures or mathematical objects that have the same shape and size. In other words, if one figure can be transformed into the other by a combination of translations, rotations, and reflections without changing its shape or size, then they are considered congruent.
For example, two triangles are congruent if their corresponding sides are equal in length and their corresponding angles are equal in measure. Congruence is often denoted by the symbol "≅".
Read More: Congruence of Triangles
According to the ASA Congruence Rule, if two angles and the included side of one triangle are equal in measure to two angles and the included side of another triangle, then the two triangles are congruent.
To apply the ASA Congruence Rule, you must have the following conditions met:
The Angle-Side-Angle (ASA) Congruence Rule is a criterion in geometry that determines the congruence of two triangles. According to this rule, if two angles and the included side of one triangle are exactly equal to two angles and the included side of another triangle, then the two triangles are congruent
Under ASA criterion of congruence rule, ∆ABC ≅ ∆XYZ if
By CPCT property [Corresponding Parts of Congruent Triangles are equal], we can further imply the following as well:
From the given two triangles, ABC and DEF, in which:
∠B = ∠E, and ∠C = ∠F and the BC = EF
To Prove: ∆ ABC ≅ ∆ DEF
To prove the congruence of the two triangles, the three cases involved are
Case 1: Let AB = DE
👁 Proof-of-ASA-Congruence-Rule
So, from SAS Rule we get, ∆ ABC ≅ ∆ DEF
Case 2: AB > DE.
Now take a point P on AB such that it becomes PB = DE.
👁 Proof-of-ASA-Congruence-Rule-02
Now consider ∆ PBC and ∆ DEF,
It is noted that in triangle PBC and triangle DEF,
From construction, PB = DE
Given,∠ B = ∠ E
BC = EF
So, we conclude that, from the SAS congruence axiom
∆ PBC ≅ ∆ DEF
Since the triangles are congruent, their corresponding parts of the triangles are also equal.
So, ∠PCB = ∠DFE
But, we are provided with that
∠ACB = ∠DFE
So, we can say ∠ACB = ∠PCB
This condition is possible only if P coincides with A or when BA = ED
So, ∆ ABC ≅ ∆ DEF (From SAS axiom)
Case 3: If AB < DE,
Let's take a point M on DE such that it becomes ME = AB,
Repeating the arguments as given in Case (ii), we can conclude that AB = DE and so we get
∆ ABC ≅ ∆ DEF.
The key difference between ASA and AAS congruence rule is listed as follows:
| Criteria | ASA Congruence Rule | AAS Congruence Rule |
|---|---|---|
| Components | Two angles and sides between them | Any two angles and any one side. |
Sequence | The congruent elements must follow an angle-side-angle sequence in both triangles. | Sequence of angle and sides doesn't matter. |
| Example | Consider two right triangles, △ABC (right angle at B) and △DEF (right angle at E). Then,
⇒ △ABC ≅ △DEF (by ASA) | Consider two triangles, △ABC and △DEF. Then,
⇒ △ABC ≅ △DEF (by AAS) |
Note: If two angles of a triangle are equal, then, by the angle sum property of a triangle, we can easily conclude that the third angle is also equal. Thus, if any triangle is proven to be congruent by the ASA criterion, it can also be easily proved by the AAS criterion.
In Class 9 geometry, the Angle-Side-Angle (ASA) Congruence Rule is a very important principle used to establish the congruence of two triangles. This rule specifies that if two angles and the included side of one triangle are equal to two angles and the included side of another triangle, then the two triangles are congruent.
Problem 1: Prove that △CBD ≅ △ABD from the given figure.
👁 Solved-Examples-on-ASA-Congruence-Rule-01
Solution:
Given: AD∥EC, BD≅BC
To prove: △ABD ≅ △EBC
Proof:
AD ⊥ EC [Given]
∠D = ∠C [Alternate Interior angles theorem]
BD = BC [Given]
∠ABD = ∠EBC [Vertical angles congruence theorem]
Thus, by ASA Congruence criteria,
△ABD ≅ △EBC
Q1: In the diagram, AB ⊥ AD, DE ⊥ AD, and AC ≅ DC. Prove that △ABC ≅ △DEC.
👁 Solved-Examples-on-ASA-Congruence-Rule-03
Q2: Use the ASA congruence theorem to prove that △NQM ≅ △MPL.