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NCERT Theorem 1.5 : Let x be a rational number whose decimal expansion terminates. Then x can be expressed in the form, where p and q are coprime, and the prime factorization of q is of the form 2n5m, where n, m are non-negative integers.
NCERT Theorem 1.6 : Let x = be a rational number, such that the prime factorization of q is of the form 2n5m, where n, m are non-negative integers. Then x has a decimal expansion which terminates.
Solution:
(i)
By doing prime factorization of denominator, we get
3125 = 5×5×5 = 53
As denominator is in the form 2n5m only where n=0 and m=3.
According to Theorem 1.6,
will have a terminating decimal expansion.
(ii)
By doing prime factorization of denominator, we get
8 = 2×2×2 = 23
As denominator is in the form 2n5m only where n=3 and m=0.
According to Theorem 1.6,
will have a terminating decimal expansion.
(iii)
By doing prime factorization of denominator, we get
455 = 5×7×13
As denominator is not in the form 2n5m only.
According to contradiction of Theorem 1.6,
will have a non-terminating decimal expansion.
(iv)
By doing prime factorization of denominator, we get
1600 = 2×2×2×2×2×2×5×5 = 2652
As denominator is in the form 2n5m only where n=6 and m=2.
According to Theorem 1.6, 1
will have a terminating decimal expansion.
(v)
By doing prime factorization of denominator, we get
343 = 7×7×7 = 73
As denominator is not in the form 2n5m only.
According to contradiction of Theorem 1.6,
will have a non-terminating decimal expansion.
(vi)
Prime factorization of denominator, we have
= 2352
As denominator is in the form 2n5m only where n=3 and m=2.
According to Theorem 1.6,
will have a terminating decimal expansion.
(vii)
Prime factorization of denominator, we have
= 225775
As denominator is not in the form 2n5m only.
According to contradiction of Theorem 1.6,
will have a non-terminating decimal expansion.
(viii)
by doing prime factorization of denominator, we get
5 = 51
As denominator is in the form 2n5m only where n=0 and m=1.
According to Theorem 1.6,
will have a terminating decimal expansion.
(ix)
by doing prime factorization of denominator, we get
50= 2×5×5 = 2152
As denominator is in the form 2n5m where n=1 and m=2.
According to Theorem 1.6,
will have a terminating decimal expansion.
(x)
by doing prime factorization of denominator, we get
210 = 2×3×5×7
As denominator is not in the form 2n5m only.
According to contradiction of Theorem 1.6,
will have a non-terminating decimal expansion.
Solution:
(i)
= 0.00416
(ii)
= 2.125
(iv)
= 0.009375
(vi)
= 0.0115
(viii)
= 0.4
(ix)
= 0.7
(i) 43.123456789
(ii) 0.120120012000120000. . .
(iii) 43.123456789
Solution:
(i) 43.123456789
As this is a rational number whose decimal expansion terminates. Then it can be expressed in the form, where p and q are coprime, and the prime factorization of q is of the form 2n5m, where n, m are non-negative integers.
= 43123456789 / 109
= 43123456789 / 29 × 59
(ii) 0.120120012000120000..............
As given decimal number expansion is non-terminating and non-repeating, then it is not a rational number. Then it can't be expressed in the form, where p and q are coprime, and the prime factorization of q is of the form 2n5m, where n, m are non-negative integers.
(iii) 43.
As given decimal number expansion is non-terminating and repeating, then it is a rational number. Then it can be expressed in the form, where p and q are coprime, but the prime factorization of q is not in the form of 2n5m only, where n, m are non-negative integers
Exercise 1.4 of NCERT Class 10 Chapter 1 - Real Numbers focuses on revisiting rational numbers and their decimal expansions, as well as introducing irrational numbers. It reinforces the concept that rational numbers have either terminating or non-terminating repeating decimal expansions, while irrational numbers have non-terminating, non-repeating decimal expansions. The exercise also covers operations with irrational numbers, proving irrationality, and understanding the properties of rational and irrational numbers on the number line.