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(i) the area of that part of the field in which the horse can graze.
(ii) the increase in the grazing area if the rope were 10 m long instead of 5 m. (Use π = 3.14)
Solution:
(i) Horse with graze=∅/(360°) × π × r2
= 90°/360° × 3.14 × 5 × 5
= 78.5/4
=19.625cm2
Area of circle the length of rope is increased to 10m
=∅/(360°) × π × r2
=90°/360° × 3.14 × 10 × 10
=314/4
=78.5cm2
(ii) Increasing in grazing area=78.5m2-19.635m2=58.875m2
(i) the total length of the silver wire required.
(ii) the area of each sector of the brooch.
Solution:
(i) Total length of silver wire required=circumference of broach+5diameter
=5 × 35 mm × πd
=175+22/7 × 35
=175+110
=285mm
(ii) Area of each sector=1/10×Area of circle
=1/10×π×r2
=1/10×22/7×35/2×35×2
=11×35/4
=385/4mm2
Solution:
Total ribs in umbrella=8
Radius of umbrella is =45cm
Area between the two consecutive ribs=1/8π×r2
=1/8×22/7×45×45cm2
=22275/28
Solution:
Angle made by sector=∅=115°
r=25cm
Total area clean at each sweep of the blades=2×Area of sector
=2×∅/(360°)×π×r2
=2×(115°)/(360°)×22/7×25×25cm2
=23×11×25×25cm2
=158125/126cm2
=1254.96cm2
The total area clean at each sweep of blades=1254.96cm2
Solution:
(Use π = 3.14)
Distance over which light fall =r=16.5km
Angle made by the sector=∅=80°
Area of the sea over which the ships are warned=Area of sector
=∅/(360°)×π×r2
=(80°)/(360°)×3.14×16.5×16.5
=1709.73
=189.97km2
The area of ships is +warned =189.97km2
Solution:
Total equal designs==6
Radius =28cm
Cost for making design=RS.035 per cm2
∠O=360°/6=60°
Area of 1 design =Area of sector-Area of triangle
=∅/(360°)×π×r2×-
Solution:
Area of sector angle p=p/360×2πr2
Therefore, option (D) is correct.