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Solution:
We have,
=
=
=
=
=
=
We know,. So, we have,
= 4 log 5
Solution:
We have,
=
=
We know,. So, we have,
=
As, we get,
=
Solution:
We have,
=
=
=
As, we get,
=
= (loge a)2
Solution:
We have,
=
=
As, we get,
=
=
Solution:
We have,
=
=
=
=
As, we get,
= log a + log b
= log (ab)
Solution:
We have,
=
=
=
=
=
=
As, we get,
= (log 3 ā log 2)2
=
Solution:
We have,
=
=
=
=
As, we get,
= 2(log2)2
Solution:
We have,
=
=
=
=
As, we get,
= m log a ā n log b
= log am ā log bn
=
Solution:
We have,
=
=
=
As, we get,
= log a + log b + log c
= log (abc)
Solution:
We have,
=
Let x ā 2 = h. So, we get,
=
=
=
=
We know,. So, we have,
= log a
Solution:
We have,
=
=
=
As, we get,
= log 5 + log 3 + log 2
= log (5Ć3Ć2)
= log 30
Solution:
We have,
=
Let 1/x = h. We get,
=
=
As, we get,
= log a
Solution:
We have,
=
=
=
=
=
=
Asand, we get,
=
=
=
Solution:
We have,
=
=
=
As, we get,
= log a + log b ā log c ā log d
= log a+ log b ā (log c + log d)
= log ab ā log cd
=
Solution:
We have,
=
=
Asand, we get,
= log e + 1
= 1 + 1
= 2
Exercise 29.10 Set 1 covers evaluating limits of various functions, including algebraic, trigonometric, and exponential functions. Students learn to apply limit rules and techniques, such as the product rule, quotient rule, and chain rule. Limits measure the behavior of functions as the input changes. Understanding limits is crucial for calculus and its applications. Practice questions reinforce learning and application. Limits help model real-world phenomena and make predictions.