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Solution:
The box contains 1 red and 3 black balls and two balls are drawn without replacement , so the sample space associated with this event can be given as:
S = { (R,B1), (R,B2), (R,B3), (B1,R), (B1,B2), (B1,B2), (B2,R), (B2,B1), (B2,B3), (B3,R), (B3,B1), (B3,B2) }
Solution:
When a pair of dice is rolled, then there are in total 6 x 6 = 36 possible outcomes.
The term doublet refers to the event when the pair of dice after rolling has outcomes as (1,1), (2,2), (3,3), (4,4), (5,5), (6,6), when a double is obtained then again the coin is tossed and we have outcome as either head (H) or tail (T).
Therefore, total number of elementary events = (36-6) + 6 x 2 = 30 + 12 = 42.
Solution:
When two coins are tossed, then we have four possible outcomes as HH, HT, TH, TT. Now for those cases where in second draw head comes, we throw a die, then the sample space is written as:
S' = { (HH,1), (HH,2), (HH,3), (HH,4), (HH,5), (HH,6),
(TH,1), (TH,2), (TH,3), (TH,4), (TH,5), (TH,6) }
Therefore, sample space for the entire experiment can be written as:
S = { (HT), (TT). (HH,1), (HH,2), (HH,3), (HH,4), (HH,5), (HH,6), (TH,1), (TH,2), (TH,3), (TH,4), (TH,5), (TH,6) }
Solution:
Since, we have identical balls inside the bag, we can denote each red ball using a common notation as R and similarly each black ball can be denoted using symbol B.
So, after first draw the sample space will be S1 = {R,B}, the ball is again put back in the bag, so again for second draw sample space will be S2 = {R,B}.
Hence, sample space for the entire event is S = { RR, RB, BR, BB }
Solution:
Three items stored in the lot can be: (a) all defective (b) all non-defective (c) a mixture of both defective and non-defective items.
Therefore, the possible sample space associated with this experiment can be given as:
S = {DDD, DDN, DND, NDD, NNN, NND. NDN, DNN }
(i) What is the sample space if we are interested in knowing whether it is a boy or girl in the order of their births.
(ii) What is the sample space if we are interested in the number of boys in a family?
Solution:
According to the question, if a family consists of two children then sample space can be given as:
(i) S = { (B1,B2), (B1,G2), (G1,B2), (G1,G2) }, the number represents the first and second child.
(ii) Since, there can be at most two children, there are three possibilities:
a) the family has 0 boys
b) the family has 1 boy
c) the family has 2 boys
Hence, the sample space S = {0,1,2}
Solution:
If we pick red colored dice and draw its sample space can be given as:
S1 = { (R,1), (R,2), (R,3), (R,4), (R,5), (R,6) }
similarly, If we pick red colored dice and draw its sample space can be given as:
S2 = { (B,1), (B,2), (B,3), (B,4), (B,5), (B,6) }
similarly, If we pick white colored dice and draw its sample space can be given as:
S3 = { (W,1), (W,2), (W,3), (W.4), (W,5), (W,6) }
Hence, sample space for the entire experiment = S1 U S2 U S3
= { (R,1), (R,2), (R,3), (R,4), (R,5), (R,6),
(B,1), (B,2), (B,3), (B,4), (B,5), (B,6),
(W,1), (W,2), (W,3), (W.4), (W,5), (W,6) }
Solution:
There are in total 2 rooms.
Rooms P Q Boys 2 1 Girls 2 3 We can select a room in two ways: either P or Q, also selecting a person from a room can be done in from P in 4 ways. Similarly, from Q it can be done in 4 ways.
Therefore, sample space for this experiment can be written as:
S = { (P,B1), (P,B2), (P,G1), (P,G2),
(Q,B3), (Q,G3), (Q,G4), (Q,G5) }
Solution:
Out of two balls, if we draw a ball, it will be either red (R) or white (W).
When a white ball is drawn, it is replaced and then again a ball is drawn, therefore sample space
S1 = { (W,W), (W,R) }
Also, if a red ball is drawn then a die is rolled, therefore sample space
S2 = { (R,1), (R,2), (R,3), (R,4), (R,5), (R,6) }
Hence, sample space for the entire experiment, S = S1 U S2
S = { (W,W), (W,R), (R,1), (R,2), (R,3), (R,4), (R,5), (R,6) }
Solution:
Since, we have identical black balls inside the box, we can denote each black ball using a common notation as B. Now, sample space for drawing two balls without replacement can be written as:
S = { (W,B), (B,W), (B,B) }
Solution:
Sample space for throwing a die:
S1 = { 1, 2, 3, 4, 5, 6 }
If the even number turns up on the dice, then a coin is tossed, so
S2 = { (2,H), (2,T), (4,H), (4,T), (6,H), (6,T) }
whereas when an odd number turns up on the dice, then a coin is tossed two times, so
S3 = { (1,HH), (1,HT), (1,TH), (1,TT), (3,HH), (3,HT),(3,TH), (3,TH), (5,HH), (5,HT), (5,TH), (5,TT) }
Therefore, sample space for the entire experiment, S = S2 U S3
S = { (2,H), (2,T), (4,H), (4,T), (6,H), (6,T),
(1,HH), (1,HT), (1,TH), (1,TT), (3,HH), (3,HT),
(3,TH), (3,TH), (5,HH), (5,HT), (5,TH), (5,TT) }
Solution:
According to the question the die keeps on rolling till we not get a six. So, the sample space can be written as:
S = { 6, (1,6), (2,6), (3,6), (4,6), (5,6), (1,1,6), (1,2,6), (1,3,6), (1,4,6), (1,5,6), (2,1,6), (2,2,6), (2,3,6), ........... }
Exercise 33.1 Set 2 covers probability concepts, including experimental probability, theoretical probability, and probability of events. Students learn to calculate probabilities using formulas and theorems. Understanding probability is crucial for statistics, data analysis, and real-world applications.