![]() |
VOOZH | about |
Solution:
Matrix form of the given equation is AX = B
i.e.
∴ |A| =
∴ Solution is unique.
Now, X = A-1B = (adj.A)B
Therefore, x=1, y=1/2, z=3/2
Solution:
Matrix form of the given equation is AX = B
i.e
∴ |A| =
∴ Solution is unique.
Now, X = A-1B = (adj.A)B
Therefore, x = 2, y = -1, z = 1
Solution:
Matrix form of given equation is AX = B
i.e.
∴ |A| =
∴ Solution is unique.
Now, X = A-1B = (adj.A)B
Therefore, x = 1, y = 2, z = -1
Solution:
Matrix form of given equation is AX = B
i.e.
∴ |A| =
∴ Solution is unique.
Now, X = A-1B = (adj.A)B
Therefore, x = 2, y = 1, z = 3
Solution:
Given: A=
Now, |A|=
∴ |A|=
Means, A-1 exists.
And A-1 =(adj.A)......(1)
Now,
∴ adj. A =
From eq. (1),
A-1=
Now, Matrix form of given equation is AX = B
i.e.
∵ Solution is unique.
∴ X=A-1B
⇒
Therefore, x = 1, y = 2, z = 3
Solution:
Let Rs x, Rs y, Rs z per kg be the prices of onion, wheat and rice respectively.
A.T.Q.
4x+3y+2z=60
2x+4y+6z=90
6x+2y+3z=70
Matrix form of equation is AX = B
where, A=,B=and X=
=>
Now, |A|=
∴ Solution is unique
Now, X=A-1B=(adj. A)B......(1)
Now,
∴ (adj.A)=
From eqn.(1)
Therefore, x = 5, y = 8, z = 8
Hence, the cost of onion, wheat and rice are Rs. 5, Rs 8 and Rs 8 per kg.