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Solution:
We have,
y = sin (3x + 5)
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y = tan2 x
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y = tan (x + 45°)
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y = sin (log x)
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y = esin √x
On differentiating y with respect to x we get,
On using chain rule, we have
On using chain rule again, we have
Solution:
We have,
y = etan x
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y = sin2 (2x + 1)
On differentiating y with respect to x we get,
On using chain rule, we have
On using chain rule again, we have
As sin 2A = 2 sin A cos A, we get
Solution:
We have,
y = log7 (2x − 3)
As , we have
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y = tan 5x°
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y = logx 3
As , we get
y =
On differentiating y with respect to x we get,
On using chain rule, we have
As , we get
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y = (log sin x)2
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
On using quotient rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
On using quotient rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using product rule, we have
On using chain rule, we have
Solution:
We have,
y = sin(log sin x)
On differentiating y with respect to x we get,
On using chain rule, we have
On using chain rule again, we have
Solution:
We have,
y = etan 3x
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Exercise 11.2 | Set 1 focuses on applications of derivatives. It covers topics such as finding the rate of change, velocity and acceleration problems, and optimization. Students are expected to apply differentiation techniques to solve real-world problems, interpret the meaning of derivatives in various contexts, and use derivatives to find maximum and minimum values of functions.