![]() |
VOOZH | about |
Chapter 11 of RD Sharma's Class 12 Mathematics textbook covers Differentiation, a fundamental concept in calculus. Exercise 11.2 Set 2 typically focuses on more advanced differentiation techniques, including the differentiation of composite functions, implicit differentiation, and applications of various differentiation rules.
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
On using quotient rule, we have
Solution:
We have,
y =
y =
As , we get
y =
On differentiating y with respect to x we get,
On using chain rule, we have
On using quotient rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
I =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using quotient rule, we have
On using product rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using quotient rule and chain rule, we get
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using quotient rule and chain rule, we get
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using quotient rule, we have
On using product rule and chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using product rule and chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using product rule and chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using quotient rule, chain rule and product rule we get,
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we get
As 2 sin A cos A = sin 2A, we get
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using product rule and chain rule, we have
Solution:
We have,
y =
On rationalizing we get,
y =
y =
y =
y =
y =
y =
On differentiating y with respect to x we get,
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule, we have
On using chain rule again, we have
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using chain rule and quotient rule, we get
Solution:
We have,
y =
On differentiating y with respect to x we get,
On using quotient rule, we get
On using product rule, we get
Exercise 11.2 Set 2 in Chapter 11 of RD Sharma's Class 12 Mathematics provides a more challenging set of problems on differentiation. These questions typically involve composite functions, trigonometric functions, exponential and logarithmic functions, and combinations thereof. This set helps students apply multiple differentiation rules simultaneously and prepares them for more complex mathematical analysis.