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Solution:
Given that x = at2, y = 2at
So,
Therefore,
Solution:
Here,
x = a(θ + sinθ)
Differentiating it with respect to θ,
and,
y = a(1 - cosθ)
Differentiate it with respect to θ,
Using equation (1) and (2),
Solution:
Then x = acosθ and y = bsinθ
Then,
Therefore,
Solution:
Here,
x = aeΘ (sinθ - cosθ)
Differentiating it with respect to θ,
And,
y = aeΘ(sinθ+cosθ)
Differentiating it with respect to θ
Dividing equation (2) by equation (1)
Solution:
Here,
x = bsin2θ and y = acos2θ
Then,
Solution:
Here,
x = a(1 - cosθ) and y = a(θ + sinθ)
Then,
Therefore,
Solution:
Here,
Differentiate it with respect to t,
and,
Differentiating it with respect to t,
Dividing equation (2) and (1)
Solution:
Here,
Differentiating it with respect to t using quotient rule,
and,
Differentiating it with respect to t using quotient rule,
Dividing equation (2) by (1)
Solution:
The given equations are
x = a(cosθ +θ sinθ) and y = a(sinθ -θcosθ)
Then,
= a[-sinθ + θcosθ + sinθ] = aθcosθ
= a[cosθ +θsinθ -cosθ]
= aθsinθ
Therefore,
Solution:
Here,
Differentiating it with respect to θ using product rule,
and,
Differentiating it with respect to θ using product rule and chain rule
Exercise 11.7 Set 1 in RD Sharma's Class 12 Mathematics textbook focuses on the application of derivatives to solve problems related to rates of change. This set covers problems involving instantaneous rates, average rates, and related rates in various contexts. Students are required to apply differentiation techniques to analyze how quantities change with respect to time or other variables, often in real-world scenarios involving motion, growth, or other dynamic processes.