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Solution:
Here,
Differentiate it with respect to t using chain rule,
And,
Differentiate it with respect to t using quotient rule,
Solution:
It is given that,
y = 12(1 - cos t),
x = 10(t - sin t)
Therefore,
Therefore,
Solution:
Here,
x = a(θ - sin θ)
and
y = a(1 - cos θ)
Then,
Therefore,
Solution:
Consider the given functions,
x = a sin 2t (1 + cos 2t)
and
y = b cos 2t (1 - cos 2t)
Write again the functions,
x = a sin 2t + sin 4t
Differentiate the above function with respect to t,
y = b cos 2t (1 - cos 2t)
y = b cos 2t - b cos2 2t
From equation (1) and (2)
Solution:
Here, the given function:
x = cos t (3 - 2cos2t)
x = cos t - 2cos3t
y = sin t (3 - 2 sin2t)
y = 3cos t - 2sin3t
Solution:
Here,
and
Solution:
x = 3sin t - sin3t
and,
y = 3cos t - cos3t
When,
Solution:
and,
and
Exercise 11.7 Set 3 in RD Sharma's Class 12 Mathematics textbook further expands on the application of derivatives to solve complex rate of change problems. This set introduces more advanced scenarios, often involving multiple interrelated variables or sophisticated real-world applications. Students are challenged to apply higher-order differentiation techniques, interpret complex physical situations, and analyze rates of change in multivariable systems.