![]() |
VOOZH | about |
Solution:
Let considered x - 1 = t,
so that dx = dt
Thus,
Solution:
Let I =
Solution:
I =
Hence,
Solution:
Let I =
Therefore, I =
Solution:
I =
Let us considered sinx = t
So, on differentiating, we get
cosx dx = dt
I =
Therefore, I =
Solution:
I =
Let us considered ex = t
So, on differentiating, we get
exdx = dt
Therefore, I =
Hence, I =
Solution:
I =
We already have,
Therefore, I =
Solution:
Let us assume I =
Therefore, I =
Solution:
Let us assume I =
Therefore, I =
Solution:
Let us assume I =
Therefore, I =
Solution:
Let us assume I =
Therefore, I =
Solution:
Let us assume x2 = t
On differentiating we get
2x dx = dt
Therefore, I =
Hence, I =
Solution:
I =
Let us considered x3 = t
So, on differentiating, we get
3x2dx = dt
Therefore, I =
Hence, I =
Solution:
I =
Let us considered logx = t
So, on differentiating, we get
1/x dx = dt
Therefore, I =
Hence, I =
Solution:
I =
Therefore, I =
Solution:
Let I =
I =
Exercise 19.28 in RD Sharma's Class 12 Chapter 19 on Indefinite Integrals focuses on integrating rational functions where the denominator is a fourth-degree polynomial (quartic). The key techniques used in solving these integrals include:
These problems require a strong understanding of algebraic manipulation, factorization of polynomials, and various integration techniques. Students should be comfortable with complex fractions and identifying the most efficient method for each problem.