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Solution:
We know that
so,
we know,
if
I =
then
I =
2I =
l=π
Solution:
We know that
So,
if
I =
then
I =
2I =
2I=
2I =
2I=0
I=0
Solution:
We know
So,
if
I=
then
I=
So
2I=
2I =
2I=
2I=π/6
I=π/12
Solution:
We know
So,
if
I =
then,
I =
2I =
2I =
2I =
2I=π/6
I=π/12
Solution:
We know
so,
if
then,
we know if
f(x) is even
f(x) is odd
Here, f(x) = tan2x which is even
hence,
I =
Solution:
We know
So,
if, then
So,
Solution:
We know
Hence,
if,
then
so,
Solution:
We know
hence,
if
Then,
So,
Solution:
if f(x) is even
if f(x) is odd
here, is odd and
is even
Hence,
2
Solution:
if
then,
Solution:
let,
we know that,
hence,
Solution:
Let,
we know that ,
so,
then,
Solution:
We know that,
So,
then,
I
Solution:
We know that,
so,
then,
Solution:
We know that,
Let,
hence,
Solution:
This exercise typically focuses on evaluating definite integrals using various methods and properties. Key concepts often covered include: