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Solution:
The number 35a64 is divisible by 3
β΅ The sum of its digits will also be divisible by 3
β΄ 3 + 5 + a + b + 4 is divisible by 3
β 18 + a is divisible by 3
β a is divisible by 3 (β΅ 18 is divisible by 3)
β΄ Values of a can be 0, 3, 6, 9
Solution:
β΅ The number 18x71 is divisible by 3
β΄ The sum of its digits will also be divisible by 3
β 1 + 8 + x + 7 + 1 is divisible by 3
β 17 + x is divisible by 3
The sum greater than 17, can be 18, 21, 24, 27β¦β¦
β΄ x can be 1, 4, 7 which are divisible by 3.
Solution:
β΅ The number 66784x is divisible by 9
β΄ The sum of its digits will also be divisible by 9
β 6 + 6 + 7 + 8 + 4 + x is divisible by 9
β 31 + x is divisible by 9
Sum greater than 31, are 36, 45, 54β¦β¦β¦
which are divisible by 9
β΄ Values of x can be 5 on 9
β΄ x = 5
Solution:
β΅ The number 67y19 is divisible by 9
β΄ The sum of its digits will also be divisible by 9
β 6 + 7 + y + 1 + 9 is divisible by 9
β 23 + y is divisible by 9
β΄ The numbers greater than 23 are 27, 36, 45,β¦β¦..
Which are divisible by 9
β΄ 23 + y = 27 β y = 4
Solution:
β΅ The number 3x2 is a multiple of 11
β΄ It is divisible by 11
β΄ The difference of the sum of its alternate digits is zero or multiple of 11
β΄ The difference of (2 + 3) and * is zero or multiple of 11
β If x β (2 + 3) = 0 β x - 5 = 0
Then x = 5
Solution:
β΅ The number 98125x2 is divisible by 4
β΄ The number formed by tens digit and units digit will also be divisible by 4
β΄ x2 is divisible by 4
β΄ The possible number can be 12, 32, 52, 72, 92
β΄ Value of x will be 1, 3, 5, 7, 9
Solution:
β΅ The number 67x19 is divisible by 11
β΄ The difference of the sums its alternate digits will be 0 or divisible by 11
β΄ Difference of (9 + x + 6) and (1 + 7) is zero or divisible by 11
β 15 + x - 8 = 0, or multiple of 11,
7 + x = 0 β x = -7, which is not possible
β΄ 7 + x = 11, 7 + x = 22 etc.
β x = 11 - 7 = 4, x = 22 β 7
β x = 15 which is not a digit
β΄ x = 4
Solution:
A number is divisible by 5 if its units digit is 0 or 5
But in number 981547, the units digit is 7
β΄ Dividing the number by 5,
Then remainder will be 7 β 5 = 2
Solution:
In the number 51439786, sum of digits is 5 + 1 + 4 + 3 + 9 + 7 + 8 + 6 = 43 and the given number is divided by 3.
β΄ The sum of digits must be divisible by 3
β΄ Dividing 43 by 3, the remainder will be = 1
Hence remainder = 1
Solution:
Let n = 798 = a multiple of 11 + [7 + 8 β 9] 798 = a multiple of 11 + 6
β΄ Remainder = 6
Solution:
Let n = 928174653
= A multiple of 11 + (9 + 8 + 7 + 6 + 3) - (2 + 1 + 4 + 5)
= A multiple of 11 + 33 β 12
= A multiple of 11 + 21
= A multiple of 11 + 11 + 10
= A multiple of 11 + 10
β΄ Remainder = 10
Solution:
(i) 2 but not by 4
A number is divisible by 2 if units do given is even but it is divisible by 4 if the number formed by tens digit and ones digit is divisible by 4.
β΄ The number can be 222, 342, etc.
(ii) 3 but not by 6
A number is divisible by 3 if the sum of its digits is divisible by 3
But a number is divisible by 6, if it is divided by 2 and 3 both
β΄ The numbers can be 333, 201, etc.
(iii) 4 but not by 8
A number is divisible by 4 if the number formed by the tens digit and one's digit is divisible by 4 but a number is divisible by 8 if the number formed by hundreds digit, the tens digit, and one digit is divisible by 8.
β΄ The number can be 244, 1356, etc.
(iv) Both 4 and 8 but not by 32
A number in which the number formed by the hundreds, tens, and oneβs digit, is divisible by 8. It will also divisible by 4 also.
But a number when is divisible by, 4 and 8 both is not necessarily divisible by 32 e.g., 328, 5400, etc.
(i) If a number is divisible by 3, it must be divisible by 9.
(ii) If a number is divisible by 9, it must be divisible by 3.
(iii) If a number is divisible by 4, it must be divisible by 8.
(iv) If a number is divisible by 8, it must be divisible by 4.
(v) A number is divisible by 18 if it is divisible by both 3 and 6.
(vi) If a number is divisible by both 9 and 10, it must be divisible by 90.
(vii) If a number exactly divides the sum of two numbers, it must exactly divide the numbers separately.
(viii) If a number divides three numbers exactly, it must divide their sum exactly.
(ix) If two numbers are co-prime, at least one of them must be a prime number.
(x) The sum of two consecutive odd numbers is always divisible by 4.
Solution:
(i) False, it is not necessarily that it must divide by 9.
(ii) True.
(iii) False, it is not necessarily that it must divide by 8.
(iv) True.
(v) False, it must be divisible by 9 and 2 both.
(vi) True.
(vii) False, it is not necessarily.
(viii) True.
(ix) False. It is not necessarily.
(x) True.