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In Class 8 Mathematics, understanding squares and square roots is crucial as it forms the foundation for algebra and various other mathematical concepts. Chapter 3 of RD Sharma's textbook delves into the squares and square roots exploring their properties, applications, and methods of calculation. Exercise 3.5 focuses on applying these concepts through practice problems helping the students reinforce their understanding and problem-solving skills.
Squares: A square of a number is the result of multiplying the number by itself. For example: a square of 4 is 4Γ4=16. Squares are fundamental in geometry and algebra and are used in various calculations.
Square Roots: The square root of a number is a value that when multiplied by itself gives the original number. For instance, the square root of 16 is 4 because 4Γ4=16. The Square roots are essential for solving equations and understanding geometric properties.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 12544 is 112.
Solution:
Here, by using long division method
π ImageWe found that the square root of 97344 is 312.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 286225 is 535.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 390625 is 625.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 363609 is 603.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 974169 is 987.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 120409 is 347.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 1471369 is 1213.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 291600 is 540.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 9653449 is 3107.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 1745041 is 1321.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 4008004 is 2002.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 20657025 is 4545.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 152547201 is 12351.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 20421361 is 4519.
Solution:-
Here, by using long division method,
π ImageWe found that the square root of 62504836 is 7906.
Solution:
Here, using long division method,
π ImageWe found that the square root of 82264900 is 9070.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 3226694416 is 56804.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 6407522209 is 80047.
Solution:
Here, by using long division method,
π ImageWe found that the square root of 3915380329 is 62573.
Solution:
Using long division method,
π ImageHere, we observed that 2361 is 57 more than the square of 48.
So, we have to subtract 57 from 2361 to make it a perfect square.
Solution:
Using long division method,
π ImageHere, we observed that 194491 is 10 more than the square of 441.
So, we have to subtract 10 from 194491 to make it a perfect square.
Solution:
using long division method,
π ImageHere, we observed that 26535 is 291 more than the square of 162.
So, we have to subtract 291 from 26535 to make it a perfect square.
(iv) 161605
Solution:
Using long division method,
π ImageHere, we observed that 161605 is 1 more than the square of 402.
So, we have to subtract 1 from 161605 to make it a perfect square.
Solution:
Using long division method,
π ImageHere, we observed that 4401624 is 20 more than the square of 2098.
So, we have to subtract 20 from 4401624 to make it a perfect square.
Solution:
Here, by using long division method,
π ImageNow, we observe that 5607 is 18 less than square of 75.
Therefore, we must add 18 to 5607 (18 + 5607 = 5625) to get a perfect square of 75 which is 5625.
Solution:
Here, by using long division method,
π ImageNow, we observe that 4931 is 110 less than square of 71.
Therefore, we must add 110 to 4931 (110 + 4931 = 5041) to get a perfect square of 71 which is 5041.
Solution:
Here, by using long division method,
π ImageNow, we observe that 4515600 is 25 less than square of 2125.
Therefore, we must add 18 to 4515600 (25 + 4515600 = 4515625) to get a perfect square of 2125 which is 4515625.
Solution:
Here, by using long division method,
π ImageNow, we observe that 37460 is 176 less than square of 194.
Therefore, we must add 176 to 37460 (176 + 37460 = 37636) to get a perfect square of 194 which is 37636.
Solution:
Here, by using long division method,
π ImageNow, we observe that 506900 is 44 less than square of 712.
Therefore, we must add 44 to 506900 (44 + 506900 = 506944) to get a perfect square of 712 which is 506944.
Solution:
We know that 99999 is the greatest 5-digit number.
Now, to get the greatest 5 digits square number, we have to find the smallest
number that can be subtracted to obtain a perfect square.
So, By using long division method,
π ImageNow, the remainder here is 143.
So, 143 must be subtracted from 99999 to get a perfect square.
So, 99999 - 143 = 99856.
Therefore, 99856 is the greatest 5 digits which is a perfect square.
Solution:
We know that 1000 is the smallest 4-digit number.
Now, in order to obtain the least 4 digits perfect square number, we have to find the
smallest number that can be added to obtain a perfect square.
So, By using long division method,
π ImageNow, we have to add 24 to 1000 to get a perfect square number.
So, 24 + 1000 = 1024
Therefore, 1024 is the least perfect square number with 4 digits which is a square of 32.
Solution:
We know that 100000 is the smallest 6 digit number.
Now, in order to obtain the least 6 digits perfect square number, we have to find
the smallest number that can be added to obtain a perfect square.
So, By using long division method,
π ImageNow, we have to add 489 to 100000 to get a perfect square number.
So, 489 + 100000 = 100489
Therefore, 100489 is the least perfect square number with 6 digits which is a square of 317.
Solution:
We know that 9999 is the greatest 4 digit number.
Now, to get the greatest 4 digits square number, we have to find the smallest number
that can be subtracted to obtain a perfect square.
So, By using long division method,
π ImageNow, the remainder here is 198.
So, 198 must be subtracted from 9999 to get a perfect square.
So, 9999 - 198 = 9801.
Therefore, 9801 is the greatest 4 digits which is a perfect square number.
Solution:
Given, Total number of Soldiers = 8160
Number of left out Soldiers = 60
So, number of soldiers arranged in rows to form a perfect square is 8100 (8160 - 60 = 8100)
So, the number of soldiers in each row = square root of 8100
So, β8100 = 90
Therefore, there are 90 soldiers in each row.
Solution:
Given, area of square field = 60025 m2
Speed of the cyclist = 18 km/h
= 18 Γ (1000/60 Γ 60)
= 5 m/s2
Area of square field = 60025 m2
or, (side)2 = 60025
or, side = β60025
or, side = 245 m
We know that, Total length of boundary = perimeter
= 4 * side (Perimeter of square = 4 * side of square)
= 4 Γ 245
= 980 m
Hence, Time taken to return to the starting point = 980/5 (time = distance / speed)
= 196 seconds
= 3 minutes 16 seconds
Solution:
Given, The cost of leveling and turning a square lawn = Rs 2.50 per m2
Total cost of leveling and turning a square lawn = Rs13322.50
Now, Area of square lawn = total cost of leveling and turning a square lawn / the cost of leveling and turning a square lawn
= 13322.50 / 2.50
= 5329 m2
So, the length of side of square = βarea of square (As area of square = side2)
= β5329 = 73 m
So, Total length for fencing = Perimeter (As perimeter of square = 4 * side)
= 4 * 73 = 292 m
Therefore, cost of fencing the square lawn = 5 * 292
= Rs. 1460
Solution:
We know that 999 is the greatest 3-digit number.
Now, to get the greatest 3 digits square number, we have to find the smallest number
that can be subtracted to obtain a perfect square.
So, By using long division method,
π ImageNow, the remainder here is 38.
So, 38 must be subtracted from 999 to get a perfect square.
So, 999 - 38 = 961.
961 = 312
Therefore, 961 is the greatest 3 digits which is a perfect square number.
Solution:
We will first find the square root of the given number by using the long division method,
π ImageNow, we come to know that 2300 is 4 less than square of 48.
So, 482 = 2304
Hence, 4 must be added to 2300 in order to get a perfect square.
Read More:
The Mastering squares and square roots is essential for the solving a wide range of the mathematical problems. Exercise 3.5 in RD Sharmaβs Chapter 3 provides the valuable practice in these areas reinforcing the studentβs ability to work with these fundamental concepts. Understanding and applying these skills will enhance proficiency in the algebra and prepare students for the more complex mathematical topics.