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Cube of Binomial as the name suggests is the third power of any binomial expression. Cube of Binomial follows a specific formula, which is (a + b)3 = a3 + 3a2b + 3ab2 + b3) and (a - b)3 = a3 - 3a2b + 3ab2 - b3), where (a) and (b) are the terms of the binomial.
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In this article, we will learn about the sum of cubes formula, the difference of cubes formula, and how to find a cube of binomial. At the end of this article, we have provided solved numerical questions for better understanding.
Cube of a binomial refers to the result obtained by raising a binomial expression to the power of 3. This process involves multiplying the binomial by itself twice and expanding the expression, resulting in a trinomial. The general form of the cube of a binomial, (a + b)3, is expressed as a3 + 3a2b + 3ab2 + b3, showcasing the coefficients derived from the expansion. Understanding the cube of a binomial is fundamental in algebraic expressions and polynomial manipulations.
Cube of a binomial refers to raising a binomial expression to the power of 3.
This process involves multiplying the binomial by itself twice and simplifying the resulting expression.
The formula for the cube of a binomial a + b and a - b is given by:
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(a - b)3 = a3 - 3a2b + 3ab2 - b3
(a+b)3 = (a+b)(a+b)(a+b)
โ (a2+2ab+b2) (a+b)
โ a(a2+2ab+b2) + b(a2+2ab+b2)
โa3+2a2b+ab2+a2b+2ab2+b3
โ a3+3a2b+3ab2+b3
โด (a+b)3 = a3+3a2b+3ab2+b3
(a - b)3 = (a - b)(a - b)(a - b)
โ (a - b)3 = (a - b)(a - b)(a - b)
โ (a - b)3 = (a2 - 2ab + b2)(a - b)
Using the distributive property multiply (a2 - 2ab + b2) by (a - b):
โ (a - b)3 = (a2 - 2ab + b2)(a - b) = a(a2 - 2ab + b2) - b(a2 - 2ab + b2)
Next, distribute (a) and (-b) into each term:
โ (a - b)3 = a3 - 2a2b + ab2 - a2b + 2ab2 - b3
โ (a - b)3 = a3 - 3a2b + 3ab2 - b3
โด (a - b)3 = (a3 - 3a2b + 3ab2 - b3).
The sum of cubes formula is a special case of the polynomial expansion known as the sum of cubes identity. It states that the sum of two cubes, a3+b3, can be factored into the product of a binomial and a trinomial.
a3 + b3 = (a + b)(a2 - ab + b2)
To derive a3+b3 using the sum of cubes formula, we start with the formula:
(a+b)3 = a3+ 3a2b + 3ab2 + b3 = a3 + b3 + 3ab(a + b)
โ (a+b)3 - 3ab(a + b) = a3 + b3
โ [(a+b)2 - 3ab](a + b) = a3 + b3
โ [a2 + b2 + 2ab - 3ab](a + b) = a3 + b3
โ [a2 + b2 - ab](a + b) = a3 + b3
The difference of cubes formula states that the difference of two cubes, ( a3 - b3 ), can be factored into (a - b)(a2 + ab + b2). This formula is derived by expanding (a - b)(a2 + ab + b2) using the distributive property, which results in (a3 - b3). It's a helpful in algebra for factoring expressions involving the difference of two cube terms.
To derive a3- b3 using the sum of cubes formula, we start with the formula:
(a - b)3 = a3 - 3a2b + 3ab2 - b3 = a3 - b3 - 3ab(a - b)
โ (a - b)3 + 3ab(a - b) = a3 - b3
โ [(a - b)2 + 3ab](a - b) = a3 - b3
โ [a2 + b2 - 2ab + 3ab](a - b) = a3 - b3
โ [a2 + b2 + ab](a - b) = a3 - b3
To calculate cube of binomial, we can use the following steps:
Step 1: Identify the Binomial.
Suppose we have the binomial (a + b).
Step 2: Cube the Binomial.
Use the formula (a + b)3 = a3 + 3a2b + 3ab2 + b3 to expand the cube of the binomial.
Step 3: Apply the Binomial Cube Formula.
Substitute the values of ( a ) and ( b ) into the expanded expression.
Step 4: Simplify.
Combine like terms and simplify the expression.
Let's consider an example for the same.
For example, if we have ( a = 2 ) and ( b = 3 ), then:
(2 + 3)3 = 23 + 3 ยท 22 ยท 3 + 3 ยท 2 ยท 32 + 33
โ (2 + 3)3 = 8 + 3 ยท 4 ยท 3 + 3 ยท 2 ยท 9 + 27
โ (2 + 3)3 = 8 + 36 + 54 + 27
โ (2 + 3)3 = 125
โด (2 + 3)3 = 125
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Example 1: Find the cube of the binomial (x + 2).
Solution:
To find the cube of the binomial (x + 2), we'll apply the formula for the cube of a binomial, which is:
(a + b)3 = a3 + 3a2b + 3ab2 + b3
Here, a = x and b = 2.
Plugging these values into the formula, we get:
(x + 2)3 = x3 + 3x2(2) + 3x(2)2 + 23
= x3 + 6x2 + 12x + 8
So, the cube of the binomial (x + 2) is x3 + 6x2 + 12x + 8
Example 2: Calculate the cube of the binomial (3y - 4).
Solution:
To calculate the cube of the binomial (3y - 4), we'll use the formula for the cube of a binomial:
(a - b)3 = a3 - 3a2b + 3ab2 - b3
Here, a = 3y and b = 4
Plugging these values into the formula, we get:
(3y - 4)3 = (3y)3 - 3(3y)2(4) + 3(3y)(4)2 - 43
= 27y3 - 3(9y2)(4) + 3(3y)(16) - 64
= 27y3 - 108y2 + 144y - 64
โด the cube of the binomial (3y - 4) is 27y3 - 108y2 + 144y - 64
Example 3: Determine the value of (2a - 1)3.
Solution:
Using the formula for the cube of a binomial:
(a + b)3 = a3 + 3a2b + 3ab2 + b3
Here, a = 2a and b = -1. Plugging these values into the formula, we get:
(2a - 1)3 = (2a)3 + 3(2a)2(-1) + 3(2a)(-1)2 + (-1)3
= 8a3 - 12a2 + 6a - 1
So, the value of (2a - 1)3 is 8a3 - 12a2 + 6a - 1
Example 4: Find the cube of the binomial (b + 5).
Solution:
To find the cube of the binomial (b + 5), we'll apply the formula for the cube of a binomial, which is:
(a + b)3 = a3 + 3a2b + 3ab2 + b3
Here, a = b and b = 5
Plugging these values into the formula, we get:
(b + 5)3 = b3 + 3b2(5) + 3b(5)2 + 53
= b3 + 15b2 + 75b + 125
So, the cube of the binomial (b + 5) is b3 + 15b2 + 75b + 125
Q1. Evaluate (4z - 6)3.
Q2. Find the cube of (m + 7).
Q3. Calculate (2t - 9)3.
Q4. Determine the cube of the binomial (n - 2).
Q5. Find the value of (6p + 1)3