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Expanding brackets (also known as "expanding parentheses") is a method in algebra where we remove brackets by multiplying each term inside the bracket by the term outside it.
Expanding brackets is commonly used when dealing with expressions like a(b + c) or more complex ones like (x + 2)(x + 3).
Example 1: Expand: 4(x + 7)
Solution:
Given expression: 4(x + 7)
Multiply term outside the bracket by each term inside the bracket:
4(x + 7) = 4 × x + 4 × 7
Simplify: = 4x + 28
4(x + 7) = 4x + 28
Example 2: Expand: (x + 5)(x - 2) Using FOIL
Solution:
Apply FOIL method (First, Outer, Inner, Last):
First: x × x = x2
Outer: x × -2 = -2x
Inner: 5 × x = 5x
Last: 5 × -2 = -10Combine terms: x2 - 2x + 5x - 10
Simplify by combining like terms: = x2 + 3x - 10
Example 3: Expand 3(x + 2)(x − 5)
Solution:
- First: x⋅x = x2
- Outside: x⋅(−5) = −5x
- Inside: 2⋅x = 2x
- Last: 2⋅(−5) = −10
Combine terms: x2 − 5x + 2x − 10 = x2 − 3x − 10
Now multiply each term by 3: 3(x2 − 3x − 10) = 3x2 − 9x − 30
Result: 3x2 − 9x − 30
Example 4: Expand: (x + 4)2
Solution:
Given expression: (x + 4)2
Applying formula: (a + b)2 = a2 + 2ab + b2
(x + 4)2 = x2 + 2 × (x × 4) + 42
Calculate each term: = x2 + 8x + 16
Example 5: Expand (x + 1)(x - 2)(x + 3)
Solution:
Expand the first two brackets: (x + 1)(x - 2) = x2 - 2x + x - 2 = x2 - x - 2
Multiply the result by (x + 3): (x2 - x - 2)(x + 3) = x2 · x + x2 · 3 - x · x - x · 3 - 2 · x - 2 · 3
Calculate each term: = x3 + 3x2 - x2 - 3x - 2x - 6
Simplify: = x3 + 2x2 - 5x - 6Result: x3 + 2x2 - 5x - 6
Example 6: (2x - 3y)(x + 4y)
Solution:
Use foild method,
- First: 2x · x = 2x2
- Outside: 2x · 4y = 8xy
- Inside: -3y · x = -3xy
- Last: -3y · 4y = -12y2
Combine like terms: 2x2 + 8xy - 3xy - 12y2 = 2x2 + 5xy - 12y2
Result: 2x2 + 5xy - 12y2
Question 1. Expand: 5(x + 2)
Question 2. Expand: -3(2x - 4)
Question 3. Expand: (x + 6)(x - 3)
Question 4. Expand: (2x + 5)(x - 1)
Question 5. Expand and Simplify: (x - 4)2
Question 6. Expand: (3x + 2)(x - 5)
Question 7. Expand and Simplify: (x + 3)(x - 2)(x + 1)
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