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Functions are a fundamental topic in algebra, taught in Classes 11 and 12. This guide will explain key concepts related to functions in algebra, provide solved examples, and offer function practice questions to help you excel in exams. Here, you’ll gain the skills needed to solve various functions questions with confidence.
Table of Content
A function is a fundamental concept in mathematics, particularly in algebra, where it describes a relationship between a set of inputs and a set of permissible outputs. Each input is related to exactly one output. The set of inputs is called the domain, and the set of outputs is called the codomain.
In more formal terms, a function f from a set A (the domain) to a set B (the codomain) is a rule that assigns each element x in A exactly one element y in B. This relationship is often written as f: A→B, and f(x) = y.
Some of the important formulas required to solve questions of functions are mentioned below:
(f + g)(x) = f(x) + g(x)
(f − g)(x) = f(x) − g(x)
(αf)(x) = αf(x)
(fg)(x) = f(x).g(x)
(f / g)(x) = f(x) / g(x)
gof(x) = g(f(x))
ho(gof)(x) = (hog)of(x)
(gof)-1(x) = f-1og-1(x)
Below added are some solved functions questions with solution based on the concept on Functions.
To find the inverse, interchange x and y and solve for y.
x = 4y − 3
Solve for y:
y = (x + 3)/4
So, the inverse function is f-1(x) = (x + 3)/4
Given functions are
f(x) = 2x + 3
g(x) = x2
So, now we need to find (f + g)(x),
(f + g)(x) = f(x) + g(x)
(f + g)(x) = (2x + 3) + x2
So, (f + g)(x) = 2x + 3 + x2.
Given functions are
f(x) = sin(x)
g(x) = cos(x)
So, we need to need to find (f−g)(x),
(f − g)(x) = f(x) − g(x)
(f − g)(x) = sin(x) − cos(x)
So, (f − g)(x) = sin(x) − cos(x).
Given function is
f(x) = 3x2
So, we need to calculate (2f)x
(2f)x = 2.f(x)
= 2.3x2
= 6x2
So, (2f)x = 6x2.
Given functions are
f(x) = x + 1
g(x) = x − 2
So, we need to calculate (f⋅g)(x),
(f⋅g)(x) = f(x)⋅g(x)
(f⋅g)(x) = (x + 1)(x − 2)
(f⋅g)(x)=x2 −2x + x − 2
(f⋅g)(x) = x2 − x − 2
So, (f⋅g)(x) = x2 − x − 2.
Given functions are
f(x) = 1/x
g(x) = x2
So, we need to calculate (f/g)(x)
(?/?)(?) = ?(?)/?(?)
(f/g)(x) = (1/x)/x2
= 1/x3
So, (f/g)(x) = 1/x3.
Given functions are
f(x) = 2x + 1
g(x) = x2
We need to calculate g∘f(x), which involves applying f(x) to g(x).
g∘f(x) = g(f(x))
g∘f(x) = g(2x + 1)
g(x) = x2
Now, substitute 2x+1 for x in the function g(x) = x2:
g∘f(x) = (2x + 1)2
g∘f(x) = 4x2 + 4x + 1
So, g∘f(x) = 4x2 + 4x + 1.
Given equation: h(x) = 2x2 − 5x + 1
Substitute x = 3:
h(3) = 2 × 32 − 5 × 3 + 1
=18−15+1
=4
So, h(3) = 4.
Given functions are
f(x) = x2
g(x) = √x
h(x) = x3
So, we need to calculate
h∘(g∘f)(x), which involves composing f(x), g(x), and h(x).
First of all, we will find g∘f(x):
g∘f(x)=g(f(x))
g∘f(x)=g(x2)
Now, substitute ?2 for x in the function g(x) = √x
g∘f(x) = √x2
g∘f(x) = x
After first, now we will calculate h(x) with g∘f(x):
h∘(g∘f)(x) = h(x)
h∘(g∘f)(x) = x3
So, h∘(g∘f)(x) = x3.
Given function is
g(x) = 5x − 2
Let y = g(x):
y = 5x − 2
Now, solve for x in terms of y:
y + 2 = 5x
x = (y+2)/5
This represents the inverse function g-1(x).
Therefore, f-1(x) = g-1(x) = 5x + 2.
Related Articles
Try out the following questions based on the function.