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To find the class width for a frequency distribution table, subtract the smallest value in the data set from the largest value. Then, divide this result by the number of classes you want to have in the table. Mathematically, itβs:
Class Width = (Largest Value β Smallest Value)/Number of Classes
In this article, we will learn how to find the Class Width for a Frequency Distribution Table and discuss some examples.
Class Width refers to the difference between a class's upper and lower boundaries in a frequency distribution. It represents the size or span of each interval or group in which data is categorized.
To calculate class width, subtract the lower boundary of a class from the upper boundary of the same class:
Class Width = Upper Boundary β Lower Boundary
Alternatively, if all classes in a frequency distribution have equal width, you can find the class width by subtracting the lower boundary of one class from the lower boundary of the next class.
A Frequency Distribution Table is a table that organizes data into different intervals (or classes) and displays the frequency (number of occurrences) of data points within each interval. It provides a visual summary of how the data is distributed across different categories or ranges.
Example of a Frequency Distribution Table:
| Class Interval | Frequency |
|---|---|
| 10 - 20 | 5 |
| 20 - 30 | 8 |
| 30 - 40 | 12 |
| 40 - 50 | 6 |
In this example, the data is divided into four class intervals, and the table shows the frequency of data points within each interval.
To find the class width for a frequency distribution table, follow these steps:
Problem 1:Given the class intervals in a frequency distribution table. Find the class width.
| Class Interval | Frequency |
|---|---|
| 10 - 20 | 6 |
| 20 - 30 | 9 |
| 30 - 40 | 7 |
| 40 - 50 | 4 |
Solution:
Choose any class interval, for example, 10 - 20.
Class Width = 20 β 10 = 10.
Thus, the class width for this distribution is 10.
Problem 2:Given the following class intervals. Find the class width.
| Class Interval | Frequency |
|---|---|
| 5 - 15 | 4 |
| 15 - 25 | 7 |
| 25 - 35 | 10 |
| 35 - 45 | 8 |
Solution:
Class Width = 15 β 5 = 10.
So, the class width is 10.
Problem 3:For a set of class intervals with boundaries as follows. Find the class width.
| Class Interval | Frequency |
|---|---|
| 50 - 60 | 5 |
| 60 - 75 | 9 |
| 75 - 90 | 12 |
Solution:
Class Width = 75 β 60 = 15.
Here, the class width is 15.
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