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Where:
an = nth term,
a = first term,
d = common difference,
n = term number.Substitute the values of a, d, and n into the formula to calculate an.
Step 1: Identify the First and Second Term:
Step 2:Find the Common Difference:
Step 3: Use the Formula:
an = a1 + (n - 1)d
Step 4: Substitute Values:
Step 5: Simplify and Solve:
Question 1: Find the 9th term of the given series, {1, 4, 7, 10, 13, 16,....}
Solution:
Term number (n) is 9,
1st-term, a1 = 1
2nd term, a2 = 4,Now find the common difference,
d = a2 - a1 = 4 - 1 = 3Now the 9th term,
a9 = First term + (Last term - 1) × common difference
= a1 + (n - 1)d
= 1 + (9 - 1) × 3
= 1 + 8 × 3
= 1 + 24
= 25So, the 9th term is 25.
Question 2: Find the 7th term of an AP whose 3rd term is 9 and 5th term is 15?
Solution:
Given
- 3rd term (a3) = 9
- 5th term (a5 ) = 15
Here we have to find common difference and first term(a1).
a3 = a1 + 2d = 9 [from the formula] ⇢ (1)
And, a5 = a1 + 4d = 15 ⇢ (2)
Solve (1) and (2),
a1 + 2d = 9 ⇢ (1)
a1 + 4d = 15 ⇢ (2)Let's apply subtraction between (1) and (2)
2d = 6, d=3So, the common difference is 3
Now put the value of d in any one equation, here put the value of d in (1)
a1 + 2d = 9
= a1 + 2 × 3 = 9 [d = 3]
= a1 = 9 - 6
= a1 = 6So the first term is 3
Now to find the 7th term,
Apply the formula for finding the nth term, here n = 7
a7 = First term + (7th term - 1) × common difference
a7 = a1 + (7 - 1)d
a7 = 3 + 6 × 3 [d = 3 and a1 = 3]
a7 = 21So the 7th term is 21.
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