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An Involutory Matrix is defined as a matrix that follows self self-inverse function, i.e., the inverse of the Involutory matrix is the matrix itself.
Only square and invertible matrices can be Involutory Matrices.
Let us consider a "2 × 2" square matrix . The given matrix is said to be an involutory matrix if satisfies the condition A2 = I
Now, comparing the terms on each side, we get
a2 + bc = 1
ab + bd = 0
b (a + d) = 0
b = 0 or a + d = 0
d = −a
So, a square matrix is said to be an involutory matrix if
- a2 + bc = 1
- d = −a
The following are some important properties of an involutory matrix:
Example 1: Verify whether the matrix given below is involutory or not.
Solution:
To prove that the given matrix is involutory, we have to prove that A2 = A.
Hence, verified.
So, the given matrix A is an involutory matrix.
Example 2: Give an example of an involutory matrix of order 2 × 2.
Solution:
A matrix is said to be an involutory matrix, if a2 + bc = 1.
Let us consider that a = 3, b = 4, c = −2 such that a2 + bc = 1.
(3)2 + (4) × (−2) = 9 − 8 = 1
We know that d = −a.
So, the involutory matrix is .
Example 3: Prove that the matrix given below is involutory.
Solution:
To prove that the given matrix is involutory, we have to prove that B = B-1.
B-1 = Adj B/ |B|
|B| = −49 − (−48) = −1
Hence, the given matrix is involutory.
Example 4: Prove that the determinant of the involutory matrix given below is always ±1.
Solution:
Let us consider of an involutory matrix "P" of order "n × n" to prove that its determinant is always ±1.
We know that a square matrix "P" is said to be involutory if and only if P2 = I.
P × P = I
Now, |P| × |P| = |I|
We know that the determinant of an identity matrix of any order is 1.
(|P|)2 = 1
|P| = √1 = ±1
Thus, the determinant of an involutory matrix of any order is always ±1.
Hence proved.