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⇱ NCERT Solutions Class 9 – Chapter 1 Number System – Exercise 1.5 - GeeksforGeeks


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NCERT Solutions Class 9 – Chapter 1 Number System – Exercise 1.5

Last Updated : 25 Apr, 2024

Question 1. Find the Value of:

(i) 641/2

641/2

= (8 Γ— 8)1/2

= (82)Β½

= 81

= 8

(ii) 321/5

321/5

= (2 x 2 x 2 x 2 x 2)1/5

= (25)β…•

= 21

= 2

(iii) 1251/3

(125)1/3

= (5 Γ— 5 Γ— 5)1/3

= (53)β…“

= 51

= 5

Question 2. Find the value of:

(i) 93/2

93/2

= (3 Γ— 3)3/2

= (32)3/2

= 33

= 27

(ii) 322/5

322/5

= (2 Γ— 2 Γ— 2 Γ— 2 Γ— 2)2/5

= (25)2⁄5

= 22

= 4

(iii) 163/4

163/4

= (2 Γ— 2 Γ— 2 Γ— 2)3/4

= (24)3⁄4

= 23

= 8

(iv) 125-1/3

125-1/3

= (5 Γ— 5 Γ— 5)-1/3

= (53)-1⁄3

= 5-1

= 1/5

Question 3. Simplify the followings:

(i) 22/3 Γ— 21/5

22/3 Γ— 21/5

= 2(2/3) + (1/5)   βΈͺ As, am Γ— an = am + n

= 213/15

(ii) (1/33)7

(1/33)7

= (3-3)7   βΈͺ As, (am)n = am x n

= 3-21

(iii) 111/2/111/4

111/2/111/4

= 11(1/2) - (1/4)    βΈͺ As, am Γ— a-n = am - n

= 111/4

(iv) 71/2 Γ— 81/2

71/2 Γ— 81/2

= (7 Γ— 8)1/2  βΈͺ As, am Γ— bm = (a Γ— b)m

= 561/2

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