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Let's break down the explanation:
When two dice are thrown, each die can land on any number from 1 to 6, inclusive. To calculate the probability of getting a sum of 9 or higher, we need to count the number of outcomes where the sum of the numbers on the faces of the two dice is 9, 10, 11, or 12.
1. Counting Favorable Outcomes:
So, in total, there are 4+3+2+1=10 favorable outcomes.
2. Total Number of Possible Outcomes:
When two dice are thrown, there are a total of 6×6=36 possible outcomes.
3. Calculating Probability:
The probability of getting a sum of 9 or higher is the ratio of the number of favorable outcomes to the total number of possible outcomes:
In summary, the probability of getting a sum of 9 or higher when two dice are thrown is approximately 0.2778.
Outcomes for a sum of 8: (2,6), (3,5), (4,4), (5,3), (6,2) — 5 outcomes
Total possible outcomes: 36
Probability: 5/36
Outcomes for a sum of 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) — 6 outcomes
Outcomes for a sum of 11: (5,6), (6,5) — 2 outcomes
Total favorable outcomes: 6 (sum of 7) + 2 (sum of 11) = 8
Probability: 8/36 = 2/9
Outcomes for a sum of 2: (1,1) — 1 outcome
Outcomes for a sum of 3: (1,2), (2,1) — 2 outcomes
Total favorable outcomes: 1 + 2 = 3
Probability: 3/36 = 1/12
Outcomes for a sum of 6: (1,5), (2,4), (3,3), (4,2), (5,1) — 5 outcomes
Outcomes for a sum of 8: (2,6), (3,5), (4,4), (5,3), (6,2) — 5 outcomes
Total favorable outcomes: 5 (sum of 6) + 5 (sum of 8) = 10
Probability: 10/36 = 5/18