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VOOZH | about |
In the study of algebraic structures, group isomorphisms and automorphisms play a fundamental role. By defining internal symmetries inside a group (automorphisms) and when two groups have the same structure (isomorphisms), these ideas aid in our understanding of the structure and symmetry of groups.
For two groups (G,+) and (G',*) a mapping f: G → G' is called an isomorphism if
In brief, a bijective homomorphism is an isomorphism.
If there exists an isomorphism from group (G,+) to (G',*). Then a group (G,+) is called isomorphic to a group (G',*)
It is written as G ≅ G'.
1. f(x)=log(x) for groups (R+,*) and (R,+) is a group isomorphism.\
2. f(x)=ax for group (Z,+) to (aZ,+) , where a is any non zero no.
3. The function f from group of cube roots of unity {} with a multiplication operation is an isomorphism to group residual classes mod(3) {{0},{1},{2}} with the operation of addition of residual classes mod(3) such that f(1)={0}, f()={1} and f()={2}.
4. f(x)=ex for groups (R,+) and (R+,*) where R+ is a group of positive real numbers and x is an integer.
5.Groups ({0,1,2,3},+4) and ({2,3,4,1},+5) are isomorphic.
NOTE:
For a group (G,+), a mapping f : G → G is called automorphism if
1. For any group (G,+) an identity mapping Ig: G → G, such that Ig(g)=g , ∀g ∈ G is an automorphism.
2. f(x)=-x for group (Z,+).
3. f(x)=axa-1 for a group (G,+) ∀a ∈ G.
4. f(z)= for groups of complex numbers with addition operation.
Remember f is complex conjugate such that if z=a+ib then f(z)===a-ib.
5.f(x)=1/x is automorphism for a group (G,*) if it is Abelian.
NOTE"
Example - 1 : Prove that (Z,+) and (2Z,+) are isomorphic.
Solution:
- Define f:Z→2Z by f(x)=2x.
- One-one: f(x)=f(y)⇒2x=2y⇒x=y.
- Onto: For every y∈2Z, there exists x∈Z such that y=2x.
- Homomorphism: f(x+y)=2(x+y)=2x+2y=f(x)+f(y).
- Hence, f is an isomorphism.
Example - 2: Show that (R+ ,⋅) and (R,+) are isomorphic via f(x)=log(x).
Solution:
- One-one: f(x)=f(y)⇒log(x)=log(y)⇒x=y.
- Onto: For every y∈R, there exists x∈R+ such that y=log(x).
- Homomorphism: f(x⋅y)=log(x⋅y)=log(x)+log(y)=f(x)+f(y).
- Hence, f is an isomorphism.
Example -3: Verify that the groups (Z6,+6) and (Z2×Z3,+) are isomorphic.
Solution:
- Define f:Z6→Z2×Z3 by f(x)=(xmod2,xmod3).
- One-one: Suppose f(x)=f(y). Then (xmod2,xmod3)=(ymod2,ymod3).This implies x≡ymod6, hence x=y.
- Onto: For every 𝑍3(a,b)∈Z2×Z3, there exists x∈Z6 such that xmod2=a and xmod3=b.
- Homomorphism: f(x+6y)=((x+y)mod2,(x+y)mod3)=f(x)+f(y).
Hence, f is an isomorphism.
Example -4: Determine if the mapping f(x)=2x from (R,+) to (R,+) is an automorphism.
Solution:
- Define f:R→R by f(x)=2x.
- One-one: Suppose f(x)=f(y). Then 2x=2y. This implies x=y.
- Onto: For every y∈R, there is no x∈R such that 2x=y (specifically, if y is odd, there is no integer x such that 2x=y).
- Homomorphism: f(x+y)=2(x+y)=2x+2y=f(x)+f(y).
Since f is not onto, it is not an automorphism.
Example - 5: Check if the function f(x)=x2defines an isomorphism between the groups (R,+) and (R+,⋅).
Solution:
- Define f:R→R+ by f(x)=x2.
- One-one: Suppose f(x)=f(y).Then x2=y2.This implies x=±y, so f is not one-one.
- Onto: For every y∈R+, choose x= √y or x=− √yin R.
- Homomorphism: f(x+y)=(x+y)2=x2+2xy+y2≠f(x)⋅f(y).
Since f is neither one-one nor a homomorphism, it is not an isomorphism.
1. Prove that the groups (Z4,+4) and (Z2×Z2,+) are isomorphic.
2. Show that (R+,⋅) and (R,+) are isomorphic via f(x)=ex.
3. Verify that the groups (Z6,+6) and (Z2×Z3,+) are isomorphic.
4. Determine if the mapping f(x)=2x from (R,+) to (R,+) is an automorphism.
5. Check if the function f(x) = x2 defines an isomorphism between the groups (R,+) and (R+,⋅).
6. Show that (Z,+) and (3Z,+) are isomorphic.
7. Prove that the function f(x)=−x is an automorphism of the group (Z,+).
8. Verify that the function is an automorphism for the group of complex numbers under addition.
9. Determine if the function f(x)=x−1 is an automorphism for the group (R∗,⋅).
10. Show that (Zn,+n) and (Z,+) are isomorphic when n is a prime number.