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To find the x-intercepts of a parabola, set y = 0 in the equation and solve for x. To find the y-intercept, set x = 0 and solve for y. For example, if the parabola is given by y = ax2 + bx + c, solving for x gives the x-intercepts, and plugging x = 0 gives the y-intercept at y = c.
Let's discuss this in detail with examples.
A parabola is a U-shaped curve that can open upward or downward. It is one of the most common shapes in algebra and geometry and can be seen in many real-life situations, like the path of a thrown ball.
A parabola is a symmetrical curve where any point is at an equal distance from a fixed point called the "focus" and a fixed line called the "directrix."
The standard form of a parabola’s equation is: y = ax2 + bx + c Here, a, b, and c are constants, and x and y are the variables. The shape and position of the parabola are determined by the values of these constants.
In general, if the directrix is parallel to the y-axis in the standard equation of a parabola is given as
y2 = 4ax
If the parabola is sideways, i.e., the directrix is parallel to the x-axis, the standard equation of a parabola becomes
x2 = 4ay
To find the x-intercept, you need to set in the quadratic equation and solve for x. Here’s how you can do it:
Example: Find x-intercept of parabola with equation .
Solution:
- Set y = 0: .
- Solve the quadratic equation:
- Divide by 2:
- Factor the equation:
- The solutions are and .
So the x-intercepts are at (3, 0) and (-1, 0).
To find y-intercept of a parabola we can use the following steps:
Example: Find the y-intercept for equation .
Solution:
- Set x = 0: .
- Simplify to get .
The y-intercept is at (0, -6).
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