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Trigonometry Formula in Class 10 is the list of all formulas used in Trigonometry useful for class 10 students in their exams. Trigonometry is the branch of mathematics that establishes the relation of the angle of a right triangle with the ratio of sides.
Trigono means triangle and metron means measure. There are in total six trigonometric ratios namely, sine, cosine, tangent, cotangent, secant, and cosecant. The Trigonometric Formulas establish relations between these Trigonometric Ratios.
In this article, we will learn Trigonometric Formulas essential for Class 10 along with the Trigonometric Ratio Table.
Read More:Trigonometry Formulas
Table of Content
Trigonometric Ratios are the ratio of sides of a right triangle for a given value of the angle denoted as theta(θ). There are six trigonometric ratios namely,
The angle θ is defined as the angle between the base and the hypotenuse of the right triangle.
Trigonometric Ratio Formulas establish the relation between Trigonometric Ratios and the sides of a right triangle. The T-Ratios Formulas Class 10 are listed below:
👁 Right-Triangle-in-Trigonometry
Trigonometric Ratio Table contains the value of all the six trigonometric ratios at some standard angles 0°, 30°, 45°, 60° and 90°.
θ | 0° | 30° | 45° | 60° | 90° |
|---|---|---|---|---|---|
sin θ | 0 | 1/2 | 1/√2 | √3/2 | 1 |
cos θ | 1 | √3/2 | 1/√2 | 1/2 | 0 |
tan θ | 0 | 1/√3 | 1 | √3 | Not defined |
cosec θ | Not defined | 2 | √2 | 2/√3 | 1 |
sec θ | 1 | 2/√3 | √2 | 2 | Not defined |
cot θ | Not defined | √3 | 1 | 1/√3 | 0 |
List of all Trigonometric Formulas essential for Class 10 is mentioned below:
Reciprocal Identities in trigonometry are:
Pythagorean Identities in trigonometry are:
Trigonometry ratios of complementary angles are:
Also, Check
Example 1: If sin A = 3/4. Calculate cos A and tan A
Solution:
cos2A = 1 - sin2A
⇒ cos2A = 1-(9/16)
⇒ cos2A = 7/16
⇒ cosA = √7/4
⇒ tanA = sinA/cosA
⇒ tanA = 3/√7
Example 2: Given 15 cot A = 8. Find sin A and sec A
Solution:
cotA = 8/15
⇒ cosec2A = 1 + cot2A
⇒ cosec2A = 1 + (64/225)
⇒ cosec2A = 289/225
⇒ cosecA = 17/15
⇒ sinA = 15/17
⇒ secA = cosecA/cotA
⇒ secA = 17/8
Example 3: Find the value of sin 45° - cos 45°.
Solution:
sin 45° = cos 45° = 1/√(2)
⇒ sin 45° - cos 45° = 0
Example 4: If tan θ + cot θ = 7. Find tan2θ + cot2θ
Solution:
tan θ + cot θ = 7
⇒ (tanθ + cotθ)2 = 49
⇒ tan2θ + cot2θ + 2tanθcotθ = 49
⇒ tan2θ + cot2θ + 2 = 49
⇒ tan2θ + cot2θ = 47
Example 5: The value of tan θ = 3/4. Find the value of sec θ.
Solution:
1 + tan2θ = sec2θ
⇒ 1 +(3/4)2 = sec2θ
⇒ sec2θ = 25/16
⇒ secθ = 5/4
Example 6: If sec θ + tan θ = 5. Find sec θ - tan θ.
Solution:
sec 2θ - tan 2θ = 1
⇒ (sec θ + tan θ)(sec θ - tan θ) = 1
⇒ 5(sec θ - tan θ) = 1
⇒ sec θ - tan θ = 1/5
1. Prove that (cos θ/(1 - tan θ)) + (sin θ/(1 - cot θ)) = sin θ + cos θ.
2. Prove that tan2θ + cot2θ +2 = sec2θ * cosec2θ.
3. If cosec θ + cot θ = 9. find cos θ.
4. If cos θ = 4/5. Find all other trigonometric ratios.
5. Find the value of sin 60° cos 30° + cos 30° sin 60°.
6. Find the value of tan 30°/cot 60°.
7. Find the value of (sin 30° + cos 30°) - (sin 60° + cos 60°).
8. If tanθ + cotθ = 1. Find the value of tan10θ + cot10θ.
9. Find the value of sin 45° + cos 45°.
10. Find the value of cos 19°/sin 71°.