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A set is a collection of distinct objects or elements. In probability theory, sets are used to represent the possible outcomes of an experiment and the events associated with those outcomes. Using sets helps us organize outcomes clearly and apply mathematical operations to calculate probabilities.
👁 Probability-1.webpFor example, when we toss a coin, the possible outcomes are Head and Tail. We can represent these outcomes as: S = {Heads, Tails}
Set operations allow us to combine, compare, or modify sets and are essential in areas like probability, logic, and mathematics. Below are the key operations on sets:
Union of Sets: The union of two sets, A and B, is the set containing all elements that belong to A, B, or both. It is denoted by A ∪ B. In probability, the union represents the event that either A or B (or both) occurs.
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
Intersection of Sets: The intersection of two sets, A and B, is the set containing the common elements present in both sets. It is denoted by A ∩ B.
P(A ∩ B) = P(A) ✖ P(B) (if A and B are independent)
Complement of a Set: The complement of a set A, denoted by A', is the set of all elements that are not in A. In probability, the complement of an event represents the event that A does not occur.
P(A') = 1 - P(A)
Difference of Sets: The difference of two sets, A and B, denoted by A − B, is the set of elements that are in A but not in B.
The sample space in probability is analogous to the universal set in set theory. It represents all possible outcomes of an experiment.
An event is a subset of the sample space, representing a particular outcome or a set of outcomes.
Consider an example in which we are intended to find the sample space of this event so we get the sample space as: S = {HH, TT, TH, HT}
Let say A be an event in which getting at least one Head. then the sample space is going to be: A = {HH, HT, TH}
And let say B be the event of getting exactly one tail: B = {HT, TH}
Question 1: If P(A) = 0.6 and P(B) = 0.5 with P(A ∩ B) = 0.2, calculate P(A ∪ B)
Given: P(A) = 0.6, P(B) = 0.5, and P(A ∩ B) = 0.2
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
⇒ P(A ∪ B) = 0.6 + 0.5 - 0.2 = 0.9
Problem 2: Consider the sample space S = {1, 2, 3, 4, 5, 6}. Let A = {2, 4, 6} and B = {1, 2, 3}. Find A ∩ B and A ∪ B.
Given: A = {2, 4, 6} and B = {1, 2, 3}
Thus, A ∪ B = {1, 2, 3, 4, 5, 6}