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Vector projection is a fundamental concept in physics and mathematics that describes how one vector influences another along a specific direction. It can be visualised as the shadow that one vector casts onto another when light is shone perpendicular to the second vector.
When working with two vectors, and, the projection of onto tells us how much of vector lies in the direction of .
Vector projection actually comes in two forms:
This is the length of the projection — a number that tells us how much of points along . It is given by:
where θ is the angle between vectors a and b.
This is the actual vector that represents the projection of onto . It gives both the magnitude and the direction (same as ). It is given by:
Pushing a Box on the Floor: Imagine you’re pushing a box at an angle to the ground using a force F.
Not all of your applied force moves the box forward; only the horizontal component of the force (the projection of F on the horizontal direction) contributes to motion. The vertical part just presses the box into the floor. This horizontal projection is Fcosθ
If is represented as A and is represented as B, The Vector Projection of A on B is given as the product of A with Cos θ where θ is the angle between A and B. The Projection Vector obtained so is a scalar multiple of A and has a direction in the direction of B.
Projection of Vector a on Vector b
a.b = Dot product of and
|b| = magnitude of
Let us assume, OP = and OQ = and the angle between OP and OQ is θ. Drawn PN perpendicular to OQ.
In the right triangle OPN, Cos θ = ON/OP
⇒ ON = OP Cos θ
⇒ ON = || Cos θON is the projection vector of on
⇒
⇒
⇒ ON =
Hence, the ON =Thus the Vector Projection of on is given as
The Vector Projection of on is given as
To find the vector projection we need to learn to find the angle between two vectors and also to calculate the dot product between two vectors.
The angle between the two vectors is given as the inverse of the cosine of the dot product of two vectors divided by the product of the magnitude of two vectors.
Let's say we have two vectors and angle between them is θ
⇒ cos θ =
⇒ θ = cos-1
Let's say we have two vectors and defined as and then the dot product between them is given as
⇒ = a1b1 + a2b2 +a3b3
Example 1. Find the projection of a vector on .
Solution:
Here, .
We know, projection of Vector a on Vector b =
Example 2. Find the projection of the vector on
Solution:
Here,
We know, projection of Vector a on Vector b =
Example 3. Find the projection of the vector on
Solution:
Here,
We know, projection of Vector a on Vector b =
Example 4. Find the projection of the vector on.
Solution:
Here,
We know, projection of Vector a on Vector b =
Example 5. Find the projection of the vector on.
Solution:
Here,
We know, projection of Vector a on Vector b =
Example 6: Find the angle between the vectors
Solution :
cos θ =
a.b = (4 x 2) + (3 x (-1)) + (( -1) x 2)
= 8 - 3 - 2 = 3|a| = √ (4) 2 + (3) 2 + (- 1) 2
|a| = √ 16 + 9 + 1 = √ 26|b| = √ (2) 2 + (- 1) 2 + (2) 2
|b| = √ 4 + 1 + 4 =|b|
= √ 9 = 3
Now computig value cos θcos θ = a.b/|a||b|
= 3 /3√26
=1/√26θ = cos-1 1/√26
θ =78.7
Question 1: Find the projection of vector on the vector
Question 2: If the project of on is 5 units, and = 10, find the angle between and
Question 3: The projection of vector on vector is equal to the projection of on
Find the ration of magnitudes
Question 4: Two vectors are given as and
If the projection of on is zero, find the value of x.
Question 5: Find the projection of vector on a unit vector in the direction of .
Example 6: Let and
Find the projection vector (not just scalar) of on , and state its direction.