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The concentration or quantity of the ions in a particular solution is termed as ionic strength of that solution. The ionic strength of an ionic compound can only be measured in the solution form and we know that an ionic compound dissociates into positive and negative ions in the water. The ionic strength of a solution is expressed using the symbol 'I'. Randall and Lewis were the first to give the concept of ionic strength in 1921. Some properties of ionic strength are as follows:
Thus, we can say that the ionic strength of an ionic compound can be calculated as half of the sum of products of the molar concentration of the ions and the square of their respective charges. The factor of 1/2 comes from the fact that the ionic compound dissociates into cations and anions. We can see that the ionic strength is directly proportional to the square of the charge on the atom and thus the ionic strength of a solution increases rapidly with the increase in charge of the ion.
The ionic strength is expressed in Moles per litre(molL-1)or Moles per kg(mol kg-1) depending upon the units taken for the concentration of the ions.
The ionic strength formula is as follows
where,
C is the molar concentration expressed in moles per litre
Z refers to the charge on the particular ionExample: The charge on OH- ion is -1, so the value of Z for hydroxide ion is -1.
Ionic strength is of great importance in chemistry such as:
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Example 1: Calculate the ionic strength of NaOH solution with a concentration of 5 mol/L.
Solution:
NaOH ------> Na+ + OH-
Given,
Concentration (C) = 5 (for both Na+ and OH- ions)
For NaOH,
Z= 1 for Na+
Z =-1 for OH-We know that Ionic strength I can be calculated using,
= 10 / 2 = 5
Thus the Ionic strength of the given solution is 5
Example 2: Calculate the ionic strength of a CaCl2 solution with a concentration of 2 mol/kg.
Answer:
CaCl2 ------> Ca+2 + Cl-
Given,
C = 2 for both the ions,
Z = +2 for Ca+2 ions
Z = -1 for Cl- ions
Using ionic strength formula,
I =10 / 2 = 5
Thus, the Ionic strength of the solution is 5.
Example 3: Calculate the concentration of the solution of KCl if the ionic strength of the solution is 20 mol/L.
Answer:
KCl -------> K+ + Cl-
Given, I = 20,
Z = +1 for K+
Z= -1 for Cl-
Using ionic strength formula,
20 = 2C / 2
20 = C
Thus the concentration of the solution of KCl is 20 moles per litre
Example 4: Compare the ionic strength of 6 mol/l of K2SO4 solution and 10 mol/l solutions of NaCl.
Answer:
For K2SO4
Given, C = 6,
Z= +1 for K+ ions
Z= -2 for SO4-2 ions
Using ionic strength formula,
= 26 / 13 = 2
For Nacl,
Given C = 10,
Z= +1 for Na+ions
Z = -1 for Cl- ions
Using Ionic Strength Formula,
= 20 / 2 =10
As 13>10, we can say that the which means that the ionic strength of potassium sulphate solution is more than the sodium chloride solution in this case.
Example 5: Calculate the ionic strength of the solution containing 4N H2SO4 and 2M HCl.
Answer:
Here there are two acids dissolved in the solution. Thus the net ionic strength of the solution will be the sum of two ions.
For H2SO4
Given, C = 4N
Normality = Molarity × n-factor (n = 2 for sulphuric acid)
C = 2M
=5
For HCl
Given, C = 2M
=2
Thus net ionic strength is calculated as,