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Molality is defined as the number of moles of solute dissolved in one kilogram of solvent. It is commonly used in chemistry because it depends only on the mass of the solvent and does not change with temperature. This makes molality very useful when studying different properties of solutions. The unit of molality is mol/kg.
Example: if one mole of a substance such as Sodium chloride is dissolved in one kilogram of water, the molality of the solution is 1 molal (1 m)
It helps in determining the concentration of a solution based on the mass of the solvent. The formula to calculate the Molality of any solution is:
Where:
The Molality of a solution has several important properties that make it useful for expressing concentration:
Molality of a solution can be calculated by using the molality formula and the given data about the mass of solute and solvent. To calculate molality, first the number of moles of solute is determined, and then it is divided by the mass of solvent in kilograms.
The steps for calculating molality are as follows:
Step 1: Find the Mass of Solute
First, note the mass of the solute given in the problem. The solute is the substance that is dissolved in the solvent.
Step 2: Calculate the Number of Moles of Solute
The number of moles of solute is calculated using the formula:
Step 3: Convert the Mass of Solvent into Kilograms
Molality is defined in terms of kilograms of solvent, so the mass of the solvent must be converted into kilograms if it is given in grams.
1 kg=1000g
Step 4: Apply the Molality Formula
The relation between molality and molarity is given by:
Where:
Example 1: Calculate the molality of 200 g of NaOH dissolved in 150 g of pure water.
Solution:
Given,
Weight of NaOH= 200 g
Weight of pure water = 150 g (0.150kg)We, know that molar mass of NaOH is 40 g/mol.
No of moles of NaOH = 200/40
= 5 moles
Formula of molality
m= (Number of moles of solute) / (Mass of solvent in kgs)
= 5 / 0.150
= 33.3 mol/kg
Therefore, the molality of solution is 33.3 mol/ kg.
Example 2: Calculate the molality of 1000 g of H2SO4 dissolved in 5 kg of water.
Solution:
Given
Weight of H2SO4 = 1000 g
Weight of water = 5 kgWe know that molar mass of H2SO4 is 98.08 g/mol.
No of moles of H2SO4 = 1000/98.08
= 10.2 moles
Formula of molality
m = (Number of moles of solute) / (Mass of solvent in kgs)
= 10.2/5
= 2.04 mol/kg.
Therefore, the molality of solution is 2.04 mol/ kg.
Example 3: Calculate the molality of 136 g of HCl dissolved in 25 g of water.
Solution:
Given
Weight of HCl = 136 g.
Weight of Water = 25 g (0.025kg)We know that molar mass of HCl is 36.46 g/mol.
No of moles of HCl = 136/36.46
= 3.73 moles
Formula of molality
m = (Number of moles of solute)/ (Mass of solvent in kgs)
= 3.73/0.025
= 149.2 mol/kg.
Therefore, the molality of solution is 149.2 mol/ kg.