numpy.hypot() in Python

This mathematical function helps user to calculate hypotenuse for the right angled triangle, given its side and perpendicular. Result is equivalent to Equivalent to sqrt(x1**2 + x2**2), element-wise. Syntax :

numpy.exp2(arr1, arr2[, out]) = ufunc 'hypot') : 

Parameters :

arr1, arr2 : [array_like] Legs(side and perpendicular) of triangle
out : [ndarray, optional] Output array with result.

Return :

An array having hypotenuse of the right triangle.

  Code #1 : Working Output :

leg1 array : [12, 3, 4, 6]
leg2 array : [5, 4, 3, 8]

Hypotenuse is as follows :
[ 13. 5. 5. 10.]

  Code #2 : Working with 2D array Output :

leg1 array : 
 [[ 0.57520509 0.12043366 0.50011671 0.13800957]
 [ 0.0528084 0.17827692 0.44236813 0.87758732]
 [ 0.94926413 0.47816742 0.46111934 0.63728903]]
leg2 array : 
 [[ 1. 1. 1. 1.]
 [ 1. 1. 1. 1.]
 [ 1. 1. 1. 1.]]

Hypotenuse is as follows :
[[ 1.15362944 1.00722603 1.11808619 1.0094784 ]
 [ 1.00139339 1.01576703 1.09347591 1.33047342]
 [ 1.37880469 1.10844219 1.10119528 1.18580661]]

  Code 3 : Equivalent to sqrt(x1**2 + x2**2), element-wise.

Output :

leg1 array : 
 [[ 0.7015073 0.89047987 0.1595603 0.27557254]
 [ 0.67249153 0.16430312 0.70137114 0.48763522]
 [ 0.68067777 0.52154819 0.04339669 0.2239366 ]]
leg2 array : 
 [[ 1. 1. 1. 1.]
 [ 1. 1. 1. 1.]
 [ 1. 1. 1. 1.]]

Hypotenuse is as follows :
[[ 1.15362944 1.00722603 1.11808619 1.0094784 ]
 [ 1.00139339 1.01576703 1.09347591 1.33047342]
 [ 1.37880469 1.10844219 1.10119528 1.18580661]]