numpy.tile() in Python

The numpy.tile() function constructs a new array by repeating array - 'arr', the number of times we want to repeat as per repetitions. The resulted array will have dimensions max(arr.ndim, repetitions) where, repetitions is the length of repetitions. If arr.ndim > repetitions, reps is promoted to arr.ndim by pre-pending 1’s to it. If arr.ndim < repetitions, reps is promoted to arr.ndim by pre-pending new axis. Syntax : 

numpy.tile(arr, repetitions)

Parameters : 

array : [array_like]Input array. 
repetitions : No. of repetitions of arr along each axis. 

Return : 

An array with repetitions of array - arr as per d, number of times we want to repeat arr 

Code 1 : 

Output : 

arr : 
 [0 1 2 3 4]
Repeating arr 2 times : 
 [0 1 2 3 4 0 1 2 3 4]

Repeating arr 3 times : 
 [0 1 2 ..., 2 3 4]

Code 2 : 

Output : 

arr : 
 [0 1 2]

Repeating arr : 
 [[0 1 2 0 1 2]
 [0 1 2 0 1 2]]
arr Shape : 
 (2, 6)

Repeating arr : 
 [[0 1 2 0 1 2]
 [0 1 2 0 1 2]
 [0 1 2 0 1 2]]
arr Shape : 
 (3, 6)

Repeating arr : 
 [[0 1 2 ..., 0 1 2]
 [0 1 2 ..., 0 1 2]]
arr Shape : 
 (2, 9)

Code 3 : (repetitions == arr.ndim) == 0 

Output : 

arr : 
 [[0 1]
 [2 3]]

Repeating arr : 
 [[0 1]
 [2 3]
 [0 1]
 [2 3]]
arr Shape : 
 (4, 2)

Repeating arr : 
 [[0 1 0 1]
 [2 3 2 3]
 [0 1 0 1]
 [2 3 2 3]
 [0 1 0 1]
 [2 3 2 3]]
arr Shape : 
 (6, 4)

Repeating arr : 
 [[0 1 0 1 0 1]
 [2 3 2 3 2 3]
 [0 1 0 1 0 1]
 [2 3 2 3 2 3]]
arr Shape : 
 (4, 6)

References : https://numpy.org/doc/stable/reference/generated/numpy.tile.html Note : These codes won’t run on online IDE's. Please run them on your systems to explore the working .