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Sometimes, while working with data, we can have an application in which we need to duplicate tuple elements by the amount of element count. This is very unique application but can occur in certain cases. Let's discuss certain ways in which this task can be performed.
Method #1: Using nested loops This is the brute force method by which this task can be performed. In this, the outer loop is for iteration to each element in list and inner loop is to add the similar element equating to length of respective tuple by outer loop.
The original list : [('1', '4', '6'), ('5', '8'), ('2', '9'), ('1',)]
The modified and extended list is : [('1', '4', '6'), ('1', '4', '6'), ('1', '4', '6'), ('5', '8'), ('5', '8'), ('2', '9'), ('2', '9'), ('1',)]Time complexity: O(n^2), where n is the total number of elements in the list of tuples.
Auxiliary space: O(n), where n is the total number of elements in the result list.
Method #2 : Using loop + chain() This is yet another way in which this task can be performed. In this, we reduce one loop, inner loop and multiply the tuples into one and flatten using chain(). It may have certain overheads depending upon different cases.
The original list : [('1', '4', '6'), ('5', '8'), ('2', '9'), ('1',)]
The modified and extended list is : [('1', '4', '6'), ('1', '4', '6'), ('1', '4', '6'), ('5', '8'), ('5', '8'), ('2', '9'), ('2', '9'), ('1',)]Time Complexity: O(n^2) where n is the length of the list "test_list".
Auxiliary Space: O(n^2) where n is the length of the list "test_list".
Method #3 : Using * operator and extend() method
The original list : [('1', '4', '6'), ('5', '8'), ('2', '9'), ('1',)]
The modified and extended list is : [('1', '4', '6'), ('1', '4', '6'), ('1', '4', '6'), ('5', '8'), ('5', '8'), ('2', '9'), ('2', '9'), ('1',)]Time complexity: O(n^2), where n is the number of tuples in the list. The nested loop runs for each tuple in the list and for each element in the tuple.
Auxiliary space: O(n), where n is the number of tuples in the list.
Method #4 : Using list comprehension and * operator
The original list : [('1', '4', '6'), ('5', '8'), ('2', '9'), ('1',)]
The modified and extended list is : [('1', '4', '6'), ('1', '4', '6'), ('1', '4', '6'), ('5', '8'), ('5', '8'), ('2', '9'), ('2', '9'), ('1',)]This method uses list comprehension to iterate through the original list and the * operator to repeat the tuple the number of times as the number of elements in the tuple. This method is more concise and more efficient than the previous methods as it only requires one pass over the original list and avoids unnecessary appending and extending.
Time complexity: O(n), where n is the number of elements in the original list.
Auxiliary space: O(n)
Method #5: Using itertools.repeat() and itertools.chain.from_iterable()
The original list : [('1', '4', '6'), ('5', '8'), ('2', '9'), ('1',)]
The modified and extended list is : [('1', '4', '6'), ('1', '4', '6'), ('1', '4', '6'), ('5', '8'), ('5', '8'), ('2', '9'), ('2', '9'), ('1',)]
The time complexity of this approach is O(nm), where n is the number of tuples and m is the maximum length of a tuple.
The auxiliary space complexity is also O(nm), for the resulting list of extended tuples.