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Python - Split list into all possible tuple pairs

Last Updated : 23 Jul, 2025

Given a list, the task is to write a python program that can split it into all possible tuple pairs combinations. 

Input : test_list = [4, 7, 5, 1, 9]

Output : [[4, 7, 5, 1, 9], [4, 7, 5, (1, 9)], [4, 7, (5, 1), 9], [4, 7, (5, 9), 1], [4, (7, 5), 1, 9], [4, (7, 5), (1, 9)], [4, (7, 1), 5, 9], [4, (7, 1), (5, 9)], [4, (7, 9), 5, 1], [4, (7, 9), (5, 1)], [(4, 7), 5, 1, 9], [(4, 7), 5, (1, 9)], [(4, 7), (5, 1), 9], [(4, 7), (5, 9), 1], [(4, 5), 7, 1, 9], [(4, 5), 7, (1, 9)], [(4, 5), (7, 1), 9], [(4, 5), (7, 9), 1], [(4, 1), 7, 5, 9], [(4, 1), 7, (5, 9)], [(4, 1), (7, 5), 9], [(4, 1), (7, 9), 5], [(4, 9), 7, 5, 1], [(4, 9), 7, (5, 1)], [(4, 9), (7, 5), 1], [(4, 9), (7, 1), 5]]

Explanation : All pairs partitions are formed.

Input : test_list = [4, 7, 5, 1]

Output : [[4, 7, 5, 1], [4, 7, (5, 1)], [4, (7, 5), 1], [4, (7, 1), 5], [(4, 7), 5, 1], [(4, 7), (5, 1)], [(4, 5), 7, 1], [(4, 5), (7, 1)], [(4, 1), 7, 5], [(4, 1), (7, 5)]]

Explanation : All pairs partitions are formed.

Approach: Using slicing and recursion

In this, we perform all pair creation from 1st element, and using recursion multiple elements are converted into pairs by appropriate partitioning.

Output:

The original list is : [4, 7, 5, 1]

Created partitions : [[4, 7, 5, 1], [4, 7, (5, 1)], [4, (7, 5), 1], [4, (7, 1), 5], [(4, 7), 5, 1], [(4, 7), (5, 1)], [(4, 5), 7, 1], [(4, 5), (7, 1)], [(4, 1), 7, 5], [(4, 1), (7, 5)]]

Time Complexity: O(n)
Auxiliary Space: O(n)

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