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The heat of reaction, also known as the Enthalpy of Reaction, is the difference in the enthalpy value of a chemical reaction under constant pressure. It is the thermodynamic unit of measurement used to determine the total amount of energy produced or released per mole in a reaction. As a result, the heat of a chemical reaction may be defined as the heat released into the environment or absorbed while the reaction occurs at constant pressure and temperature, and Joule (J) is the unit used to measure the total quantity of heat received or released.
In chemical reactions, heat is mostly transferred between the reacting system and the surroundings. Before and after the chemical transformation, the amount of heat energy is the same. In other words, the heat acquired or lost in a reacting system is equivalent to the heat gained or lost in the surroundings.
ΔH= Q
Q = m × c × ΔT
Where,
- Q = Heat of Reaction,
- m = mass of medium,
- c = specific heat capacity of the reaction medium,
- ∆T = difference in temperature of the medium.
Besides we also have another equation as,
Heat of Reaction = ΔH (products) - ΔH (reactants)
Where,
- ΔH = change in heat value
It is given that,
c = 4.2 Jg-1K-1,
m = 200 g,
ΔT = 42 – 28 ,
i.e. ΔT = 14 °C or 14 K
Here in the question, it is mentioned that a certain amount of ethanol is burned in order to raise the temperature of the water, implying that heat absorbed by water is evolved by the ethanol combustion process. The amount of heat lost in the combustion process is equal to the amount of heat gained by the water.
The amount of heat that has been changed can be determined by using formula,
Q = m × c × ΔT
Q = 200 × 4.2 × 14
Hence, Q = 11760 J
Here it is given that,
c = 4.18 J / g°C,
m = 100 g,
ΔT = 25 – 21,
i.e. ΔT = 4 K
The process results in a temperature drop, indicating that the salt dissolution tends to heat absorption from the system. Since, the heat lost by water is same as the heat absorbed by salt,
We have,
Q = m × c × ΔT
Q = 100 × 4.18 × 4
Hence, Q = 1672 J
We have,
m = 240 g,
Specific heat capacity of Iron (c) = 0.452 J / g°C,
ΔT = Final temperature - Initial temperature = 25 - 90 = -65 °Celsius
We have the formula,
Q = m × c × ΔT
By putting given values in above equation we get,
Q = 240 × 0.452 × (-65)
hence, Q = -7051.2 J
i.e. Q = -7.05 KJ
Hence, 7.05 KJ heat is released when the process takes place.
Here we are given with,
c = 4.184 J / g degrees C,
q = 650 KJ = 650000 J
ΔT = 100 - 20 = 80 Degrees Celsius
We are asked to find the Mass (m) so we have the formula,
Q = m × c × ΔT
the above equation will give us,
m = Q / (c × ΔT)
by putting given values in above equation, we will get the actual mass of carbon required,
m = 650000 / (4.184 × 80)
m = 1941.9 g
i.e. m = 194 kg
m = 60 g
ΔT = 40 - 30 = 10 degrees Celsius
q = 968 Joules
We have to find the Specific heat capacity ( c ) so we have the formula,
Q = m × c × ΔT
the above equation will give us,
c = Q / (m × ΔT)
by putting given values in the above equation we will get,
c = 968 / (60 × 10)
c = 1.613 J / g°C
In conclusion, the heat of reaction, also referred to as reaction enthalpy, represents the change in enthalpy during a specific chemical reaction at constant pressure. It serves as a thermodynamic unit to quantify the total energy, either produced or released, per mole during the reaction. This measurement is crucial for understanding energy changes in chemical processes.
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